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3 years ago

5

Determine the magnitude and direction of the force on an electron traveling 3.58 E 6 m/s horizontally to the west in a verticall

y upward magnetic field of strength 1.30 T.

1 answer:

olya-2409 [2.1K]3 years ago

4 0

Answer:banana

Explanation:

Because the amount of potassium is that

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A flatbed truck is supported by its four drive wheels, and is moving with an acceleration of 6.3 m/s2. For what value of the coe

Levart [38]

Answer:

Coefficient of static friction will be equal to 0.642

Explanation:

We have given acceleration $a=6.3m/sec^2$

Acceleration due to gravity $g=9.8m/sec^2$

We have to find the coefficient of static friction between truck and a cabinet will

We know that acceleration is equal to $a=\mu g$ , here $\mu$ is coefficient of static friction and g is acceleration due to gravity

So $\mu =\frac{a}{g}=\frac{6.3}{9.8}=0.642$

So coefficient of static friction will be equal to 0.642

3 0

3 years ago

When the Earth is closest to the Sun, it is at:

ahrayia [7]

a). Perihelion . . . the point in Earth's orbit that's closest to the Sun.
We pass it every year early in January.

b). Aphelion . . . the point in Earth's orbit that's farthest from the Sun.
We pass it every year early in July.

c). Proxihelion . . . a made-up, meaningless word

d). Equinox . . . the points on the map of the stars where the Sun
appears to be on March 21 and September 21.

5 0

3 years ago

An object is located 20.0 cm from a convex lens. The lens focuses light at a

V125BC [204]

The Answer Is : D. 20.0 cm

My Reason : These types of problems can all be solved using the lens or mirror equation.

1/20 +1/q= 1/10

q=20 cm

The image is formed behind the lens at 2f or the center of curvature.

It is real, inverted, and the same size as the object

6 0

3 years ago

The froghopper Philaenus spumarius is supposedly the best jumper in the animal kingdom. To start a jump, this insect can acceler

Kay [80]

Answer:

Part a)

$v_f = 4 m/s$

Part b)

$t = 0.001 s$

Part c)

$d = 0.815 m$

Explanation:

Part a)

As we know that initially the grass hopper is at rest at the ground position

Now the acceleration is given as

$a = 4000 m/s^2$

distance of the legs that it stretched is given as

$s = 2.0 mm$

so we have

$v_f^2 - v_i^2 = 2 a d$

$v_f^2 - 0 = 2(4000)(0.002)$

$v_f = 4 m/s$

Part b)

time taken to reach this speed is given as

$v_f - v_i = at$

$4 - 0 = 4000 t$

$t = 0.001 s$

Part c)

as the grass hopper reach the maximum height its final speed would be zero

so we will have

$v_f^2 - v_i^2 = 2 a d$

$0 - 4^2 = 2(-9.81) d$

$d = 0.815 m$

5 0

3 years ago

If I have a 10 lb ball and a 2 lb ball which

mojhsa [17]

Answer:

It would be the 10 lb ball.

Explanation:

The more that an object weighs, the more force that is needed to accelerate it.

Hope this helped

:)

6 0

3 years ago