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swat32
3 years ago
15

Which object is accelerating downward at the slowest rate? a textbook falling onto the surface of the moon a flower pot that has

been pushed out a window a pebble falling off a cliff through the air a baseball thrown from third base to first base
Physics
1 answer:
wariber [46]3 years ago
6 0

Answer:

The acceleration of textbook is downward at the slowest rate.

(a) is correct option.

Explanation:

Given that,

The object is accelerating downward at the slowest rate.

(a). a textbook falling onto the surface of the moon

(b). a flower pot that has been pushed out a window

(c). a pebble falling off a cliff through the air

(d). a baseball thrown from third base to first base

We know that,

Acceleration :

Acceleration is the product of mass of object and gravity.

a=mg

We need to find the accelerating downward at the slowest rate

According to given data,

Acceleration depends upon weight and gravity.

We have some example of free fall.

(b), (c) and (d) are the example of free fall.

In which the gravity is same.

But in option (a) textbook falling onto the surface of the moon

We know that,

The gravity on the moon is less than the earth.

So, we can say that the acceleration of textbook is downward at the slowest rate.

Hence, The acceleration of textbook is downward at the slowest rate.

(a) is correct option.

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Two isolated copper plates, each of area 0.40 m2, carry opposite charges of magnitude 7.08 × 10-10 C. They are placed opposite e
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Answer:

The potential difference between the plates is 8 V.

Explanation:

Given that,

Area of plates = 0.40 m²

Charge q=7.08\times10^{-10}\ C

Distance = 4.0 cm

We need to calculate the electric field

Using for formula of electric field

E=\dfrac{2q}{2\epsilon_{0}A}

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Put the value into the formula

E=\dfrac{7.08\times10^{-10}}{8.85\times10^{-12}\times0.40}

E=200\ V/m

We need to calculate the potential difference between the plates

Using formula of potential difference

V=E\times d

Where, E = electric field

d = distance

Put the value into the formula

V=200\times0.04

V=8\ V

Hence, The potential difference between the plates is 8 V.

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