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Kipish [7]
3 years ago
5

Calories are units that express measurement of

Physics
1 answer:
Basile [38]3 years ago
8 0

Answer:

energy

Explanation:

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GarryVolchara [31]

Answer:

kinetic energy is the answer

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3 years ago
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2. Sherlock Holmes established and ran the first ever crime laboratory.<br> True<br> False
alex41 [277]

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Explanation:

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How do I solve the equation
ioda
First you see the difference in mass numbers  238-234 = 4 
 Its is an alpha particle as it decreases the mass no by 4 .
6 0
3 years ago
Please help!! :)
Andrews [41]

Answer:

Option D. 9.47 V

Explanation:

We'll begin by calculating the equivalent resistance of the circuit. This can be obtained as follow:

Resistor 1 (R₁) = 20 Ω

Resistor 2 (R₂) = 30 Ω

Resistor 3 (R₃) = 45 Ω

Equivalent Resistance (R) =?

R = R₁ + R₂ + R₃ (series connections)

R = 20 + 30 + 45

R = 95 Ω

Next, we shall determine the current in the circuit. This can be obtained as follow:

Voltage (V) = 45 V

Equivalent Resistance (R) = 95 Ω

Current (I) =?

V = IR

45 = I × 95

Divide both side by 95

I = 45 / 95

I = 0.4737 A

Finally, we shall determine, the voltage across R₁. This can be obtained as follow:

NOTE: Since the resistors are in series connection, the same current will pass through them.

Current (I) = 0.4737 A

Resistor 1 (R₁) = 20 Ω

Voltage 1 (V₁) =?

V₁ = IR₁

V₁ = 0.4737 × 20

V₁ = 9.47 V

Therefore, the voltage across R₁ is 9.47 V.

8 0
3 years ago
What work is done by a system on its environment when an ideal gas is maintained at a constant pressure of 200 newtons/meter2 du
Crank

<u>Answer:</u>

Work done done by a system on its environment is W=40 Joules

<u>Explanation:</u>

<u>Given:</u>

Ideal gas is maintained at a constant pressure P=200 \frac{N}{m^{2}}

Change in Volume d v= -0.2 m^{3}

<u>To find:</u>  

Work done by a system during an Isobaric Process

<u>Solution:</u>  

In a Isobaric Process, constant pressure is maintained, P=200 \frac{N}{m^{2}}

According to the formula,

work done  \bold{W=P \times d v}

Substitute the values of pressure and change in volume in the above formula,

=200 \times -0.2

=40 \text { Joules }

<u>Result:</u>  

Work done done by a system W= -40 Joules

8 0
3 years ago
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