None of those choices is a device commonly used to detect
the presence of a static electric charge. One of them is a
process or technique, and is not even a 'device'.
A couple of them might be jerry-rigged to detect charge, but
that is not their intended purpose or design, and it would take
some ingenuity. They're certainly not "commonly used" in that
application.
-- Compass . . . a device that detects the presence of a magnetic
field and displays its direction.
-- Voltmeter . . . a device that displays the presence and measures
the magnitude and direction of electric potential
difference between two points.
-- Electrophoresis . . . a method of separating macro molecules
according to their size.
-- Galvanometer . . . a device used to detect the presence and
measure the magnitude and direction of
small electric currents.
Answer: opposite
Explanation:
Action reaction forces act in opposite direction to each other.
Answer:using Newton third law
Let initial velocity of block be u1=3m/s
Mass of moving block m1 =1kg
Final velocity of block =V
Mass of stationary block m2= 4kg
Since they stick together, their final velocity will be the same.
m1u1 + m2u2=(m1+m2)v
(1*3)+(0*4)=(1+4)v
3=5v
Divide both sides by 5
V=0.6
Final velocity is 0.6m/s
Explanation:
I think nebula?Sorry if I'm wrong
P = Momentum
M = Mass
t = time
v = velocity (speed)
J= Impulse
1.)
F = 100N
t = 5s
Change in momentum(P) = Ft
I see that this is not one of your equations but your equations do not work with this problem.
P = Ft
P = (100)(5)
P = 500 Ns
2.)
See if you can get this one by yourself from what I did on the last problem.
3.)
P = 25 kgm/s
M = 2.0 kg
So, you are looking for velocity (speed). Look for the equation that has momentum, mass and velocity.
Use the equation P = mv
25 = 2(v)
25 = 2v
25/ 2 = 2v/2
12.5 m/s = v
4.) Do the same for number 4.
P = 12 kgm/s
M = 1kg
P = mv
12 = 1v
12/1 = 1v/1
12 m/s = v
6.)
P = 100 kgm/s
V= 7.0m/s
P= mv
100 = m7.0
100/7 = 7.0m/7
14.28 kg = m
Try page 2 by yourself and message me or comment if you need more help. Just identify the variable you have and what you need to find and put them in an equation that fits. You can do this!!!!