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Black_prince [1.1K]
3 years ago
9

Your friend Jamie rolled a number cube and got the number 5. in his next turn he says he won’t be able to roll another 5 because

he is only expected to roll a 5 once every six rolls. Is your friend correct ? explain your answer
Mathematics
2 answers:
konstantin123 [22]3 years ago
8 0
No, the probability of getting a 5 is 1/6, but you could roll any number of fives in a row. It is just as likely to get rolled the second time as it was the first.
Gnom [1K]3 years ago
3 0

Answer:

Sample Response: Jamie is not correct. No matter how many times the cube is rolled, the probability of rolling a 5 will be 1/6.

Step-by-step explanation:

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Check the picture below.

so the perimeter of the polygon is the sum of all its sides, namely, AB + BC + CD + DA.

now, let's check how long each side is,

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\ \quad \\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
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%  (c,d)
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AB=\sqrt{3^2+10^2}\implies \boxed{AB=\sqrt{109}}\\\\
-------------------------------

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\ \quad \\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
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%  (c,d)
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\\\\
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-------------------------------

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\ \quad \\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&C&(~{{ 4}} &,&{{0}}~) 
%  (c,d)
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\end{array}
\\\\
-------------------------------\\\\
CD=\sqrt{(2-4)^2+(-1-0)^2}\implies CD=\sqrt{(-2)^2+(-1)^2}
\\\\\\
\boxed{CD=\sqrt{5}}\\\\
-------------------------------

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\ \quad \\
\begin{array}{ccccccccc}
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%  (a,b)
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