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Sphinxa [80]
3 years ago
12

I need the answer this is the last question

Mathematics
2 answers:
svp [43]3 years ago
7 0

Answer:8

Step-by-step explanation:

max2010maxim [7]3 years ago
4 0

Answer:

Hope this helps

Step-by-step explanation:

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How many pounds of a 15% copper alloy must be mixed with 700lb of a 30% copper alloy to maybe a 25.5% copper alloy
lisov135 [29]

Answer:

300\; \rm lb.

Step-by-step explanation:

Let x represent the mass (in pounds) of that 15\% copper alloy required, such that the final mixture would contain 25.5\% copper by mass.

Consider: if x pounds of that 15\% copper alloy is mixed with 700 pounds that 30\% copper alloy, what would be the mass of copper in the mixture?

  • Mass of copper in x pounds of that 15\% copper alloy: (0.15\, x)\; \rm lb.
  • Mass of copper in 700 pounds of that 30\% copper alloy: 700 \times 0.30 = 210\; \rm lb.

Therefore, the mixture would contain (210 + 0.15\, x) \; \rm lb of copper.

The mass of that mixture would be (700 + x)\; \rm lb. The mass fraction of copper in that mixture would be:

\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\%.

This ratio is supposed to be equal to 25.5\%. These two pieces of equations combine to give an equation about x:

\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\% = 25.5\%.

\displaystyle \frac{210 + 0.15\, x}{700 + x} = 0.255.

Simplify and solve for x:

210 + 0.15\, x= 0.255\, (700 + x).

(0.255 - 0.15)\, x= 210 - 0.255 \times 700.

\displaystyle x = \frac{210 - 0.255 \times 700}{0.255 - 0.15} = 300.

Therefore, 300\; \rm lb of that 15\% alloy would be required.

4 0
3 years ago
A mechanic buys $14.56 worth of parts from a supplier. If he pays for the parts with a $20 bill, how much change will he receive
GarryVolchara [31]
$20-$14.56=$5.44

The mechanic would get $5.44 back as change.
8 0
3 years ago
Read 2 more answers
I need help on this
sweet [91]
So basically you would take you your m which is 339 degrees greater than 3 so you would divide 339 by 3 and get 113 so your m= 113 degrees so for example the first question would be m<1 = 113 and so on so you would multiply 113 by the number it is greater than
6 0
3 years ago
Compute each sum below. If applicable, write your answer as a fraction.
Alex777 [14]

Answer:

First equation is -425

Second equation is 11.25

Step-by-step explanation:

First equation we can write as

\sum_{i=0}^7 5 \times (-2)^i

computing

When i=0 -> 5 \times (-2)^0 =5

When i=1 -> 5 \times (-2)^1 = -10

...

When i=7 -> 5 \times (-2)^7 = --640

then replacing each term we have

5  + (-10) + ( 20) + ( -40) +  (80) +( -160) +   320 + (-640) = -425

For the second equation we'll have 9 terms, solving in a similar fashion

When i=1 -> \frac{1}{4}1=0.25

When i=2 -> \frac{1}{4}2=0.50

When i=3 -> \frac{1}{4}3=0.75

...

When i=9 -> \frac{1}{4}9=2.25

So we have 0.25 + 0.50 + 0.75 + 1.00 + 1.25 + 1.50+ 1.75 +2.00 +2.25

4 0
4 years ago
A vacant city lot is being turned into a neighborhood garden. The neighbors want to fence in a triangular section of the lot and
ozzi

9514 1404 393

Answer:

  17 ft, 27 ft, 20 ft

Step-by-step explanation:

Let s represent the length of the shortest side. The the longest side is (2s-7) and the third side is (s+3). The perimeter is the sum of the side lengths:

  64 = s +(2s -7) +(s +3)

  64 = 4s -4 . . . . . . . . . . . collect terms

  16 = s -1 . . . . . . . . . . divide by 4

  17 = s . . . . . . . . . add 1

  2s -7 = 2·17 -7 = 27 . . . . . the length of the longest side

  s +3 = 17 +3 = 20 . . . . . . . the length of the third side

The side lengths are 17 feet, 27 feet, and 20 feet.

8 0
3 years ago
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