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77julia77 [94]
2 years ago
6

Find the sum of the series and show your process for finding each term leading to the final sum.

Mathematics
1 answer:
Crazy boy [7]2 years ago
5 0

ANSWER

\sum_{k=3}^5( - 2k + 5) =  - 9

EXPLANATION

The given series is

\sum_{k=3}^5( - 2k + 5)

This series is finite.

The expanded form is

\sum_{k=3}^5( - 2k + 5) = ( - 2 \times 3 + 5) + ( - 2 \times 4 + 5) + ( - 2 \times 5 + 5)

This simplifies to

\sum_{k=3}^5( - 2k + 5) = ( - 6 + 5) + ( - 8+ 5) + ( - 10+ 5)

\sum_{k=3}^5( - 2k + 5) = ( - 1) + ( - 3) + ( - 5)

\sum_{k=3}^5( - 2k + 5) =  - 9

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Please help and explain process too. Thank you!! ​
sergey [27]
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2 years ago
NEED URGENT HELP!! WILL GIVE BRAINLIEST
Flauer [41]

1. You need to multiply the denominator by something that will make the content of the radical be a square—so that when you take the square root, you get something rational. Easiest and best is to multiply by √6. Of course, you must multiply the numerator by the same thing. Then simplify.

\displaystyle\frac{2}{\sqrt{6}}=\frac{2}{\sqrt{6}}\cdot\frac{\sqrt{6}}{\sqrt{6}}\\\\=\frac{2\sqrt{6}}{\sqrt{6}\cdot\sqrt{6}}=\frac{2\sqrt{6}}{6}\\\\=\bf{\frac{\sqrt{6}}{3}}

2. Identify the squares under the radical and remove them.

5\sqrt{12xm^3}=5\sqrt{(4m^2)(3xm)}=5\sqrt{(2m)^2}\sqrt{3xm}\\\\=5\cdot 2m\sqrt{3xm}=\bf{10m\sqrt{3xm}}

7 0
3 years ago
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alexira [117]

a. The first variable is x and the second variable is y.

b. The equations are x+y=12 and x-y=8.

Step-by-step explanation:

Step 1:

The first step is to define the variables. The variables can be any two symbols, letters, characters, etc.

Here let the first variable be x and the let the second variable be y.

So the variables are defined as x and y.

Step 2:

The sum of the given variables is 12.

The first variable + the second variable = 12,

x+y=12.

The difference between the two variables is 4.

The first variable - the second variable = 4.

x-y=4.

Step 3:

If we add both the equations we get, 2x =16, x= 8 and y=4.

x = 8 and y = 4.

4 0
3 years ago
Which of the binomials below is a factor of this trinomial? x^2 + 3x - 4A. x+4B. x+8C. x-4D. x^2+4
Usimov [2.4K]

Given:

The equation is:

x^2+3x-4

Find-:

Binomials factor of the equation

Explanation-:

The quadratic equation,

x^2+3x-4

Solve for factor

\begin{gathered} =x^2+3x-4 \\  \\ =x^2+4x-x-4 \\  \end{gathered}

Then the factor is:

\begin{gathered} =x^2+4x-x-4 \\  \\ =x(x+4)-1(x+4) \\  \\ =(x+4)(x-1) \end{gathered}

So, the factor is x + 4

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