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solong [7]
3 years ago
9

What is the slope-intercept form equation of the line that passes through (1, 3) and (3, 7)?

Mathematics
1 answer:
34kurt3 years ago
5 0

Answer:

y=2x+1

Step-by-step explanation:

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What is the solution to this equation? 4x^2+98=0
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There is no real solution

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Find -48a divided by 8 when a =1 . Write the answer in simplest form.<br><br> The solution is
love history [14]

Answer: -6

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7 0
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the line y=2x-4 is dilated bt a scale factor of 3/2 and centered at the origin. Write an equation that represent that image of t
Veseljchak [2.6K]

Answer:  y = 2x -6

Step-by-step explanation:

Since, If (x,y) represents the coordinates of a line, then after dilation about the origin by the scale factor k, the coordinates of the resultant line will get by the rule,

(x,y)\rightarrow (kx,ky)

Here, The equation of the given line is,

y = 2x - 4

x-intercept and y-intercept of the line are (2,0) and (0,-4) respectively,

Hence, the line y = 2x - 4 will be passes through the points (2,0) and (0,-4),

By the above property,

The dilated line about the origin will be passes through the points (3,0) and (0,-6),   ( Because (3/2× 2, 3/2×0) = (3,0) and (3/2×0, 3/2×-4) = (0,-6) )

Hence, the equation of transformed line after dilation,

y-0 = \frac{-6-0}{0-3}(x-3)    

y-0=2(x-3)

y-0=2x-6

y=2x-6

7 0
3 years ago
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Let f(x) = tan(x) - 2/x. Let g(x) = x^2 + 8. What is f(x)*g(y)?
Tema [17]

Answer:

f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}

Step-by-step explanation:

We are given that

f(x)=tan(x)-\frac{2}{x}

g(x)=x^2+8

We have to find f(x)\times g(y)

To find the value of f(x)\times g(y) we will multiply f(x) by g(y)

g(y)=y^2+8

Now,

f(x)\times g(y)=(tanx-\frac{2}{x})(y^2+8)

f(x)\times g(y)=tan(x)(y^2+8)-\frac{2}{x}(y^2+8)

f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}

Hence,

f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}

5 0
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