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3 years ago

Solve each equation. |n+3|+8=15

Mathematics

2 answers:

DochEvi [55]3 years ago

5 0

Answer:

n=4

Step-by-step explanation:

First you subtract 8 from 15 which gives you 7 so it is n+3=7. then you subtract 3 from 7 which gives you 4.

Naddik [55]3 years ago

5 0

Answer:

n = 4 and n = -10

Explanation:

l n + 3 l + 8 = 15

l n + 3 l = 7

Two solutions

n + 3 = 7

n = 4

and

n + 3 = -7 (since we are dealing with absolute numbers, one side has to be multiplied by -1)

n = -10

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A battery has a lifetime that is approximately normally distributed with a mean of 600 hours and a standard deviation of 50 hour

miss Akunina [59]

Answer:

A. Your battery is likely defective since such poor performance is extremely unlikely.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If X is more than two standard deviations from the mean, it is considered an unlikely outcome.

In this question, we have that:

$\mu = 600, \sigma = 50$

Which of the following conclusions is the most appropriate given this information?

Lasted 400 hours, so X = 400.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{400 - 600}{50}$

$Z = -4$

4 standard deviations from the mean, so unlikely.

So the correct answer is:

A. Your battery is likely defective since such poor performance is extremely unlikely.

3 0

3 years ago

Jared id scheduled to work for 5/6 of an hour at the school fair. He already worked 1/3 of hour. How much longer does he have to

harkovskaia [24]

C.)1h 5/6-1/3=5/6-2/6=3/6=1h
srry if you are confused im just in a rush.....Lol

6 0

3 years ago

Read 2 more answers

What is the y-intercept of the line perpendicular to the line y = 3/4x + 3 that includes the point (-3, -3)

kipiarov [429]

A perpendicular line has an opposite reciprocal slope. This means that the new line will have a slope of -4/3x. Plug in x and y into the equation y=Mx +b where m is the slope (-4/3):
-3=(-3/4)(-3) + b
and isolate b:
b-3=(-3/4)(-3)
b=(-3/4)(-3) +3
b=9/4+3
b=21/4

The final equation is y= -4/3x + 21/4
The y intercept is (21/4).

6 0

3 years ago

Each item produced by a certain manufacturer is independently of acceptable quality with probability 0.95. Approximate the proba

Diano4ka-milaya [45]

Answer:

The probability that at most 10 of the next 150 items produced are unacceptable is 0.8315.

Step-by-step explanation:

Let X = number of items with unacceptable quality.

The probability of an item being unacceptable is, P (X) = p = 0.05.

The sample of items selected is of size, n = 150.

The random variable X follows a Binomial distribution with parameters n = 150 and p = 0.05.

According to the Central limit theorem, if a sample of large size (n > 30) is selected from an unknown population then the sampling distribution of sample mean can be approximated by the Normal distribution.

The mean of this sampling distribution is: $\mu_{\hat p}= p=0.05$

The standard deviation of this sampling distribution is: $\sigma_{\hat p}=\sqrt{\frac{ p(1-p)}{n}}=\sqrt{\frac{0.05(1-.0.05)}{150} }=0.0178$

If 10 of the 150 items produced are unacceptable then the probability of this event is:

$\hat p=\frac{10}{150}=0.067$

Compute the value of $P(\hat p\leq 0.067)$ as follows:

$P(\hat p\leq 0.067)=P(\frac{\hat p-\mu_{p}}{\sigma_{p}} \leq\frac{0.067-0.05}{0.0178})=P(Z\leq 0.96)=0.8315$

*Use a z-table for the probability.

Thus, the probability that at most 10 of the next 150 items produced are unacceptable is 0.8315.

5 0

3 years ago

I need help ASAP please

Lorico [155]

Volume of a right hexagonal pyramidd is $\frac{ \sqrt{3} }{2}a^{2}h$ where a is the base side legnth and h=height
side legnth=12
height=36
subsitute
V= $\frac{ \sqrt{3} }{2}(12^{2}) (36)$
V= $\frac{ \sqrt{3} }{2} (144)(36)$
V= $\frac{ \sqrt{3} }{2} (5184)$
V= $\frac{ 5184 \sqrt{3} }{2}$
V= $2592 \sqrt{3}$
V=4489.48 cm^3

6 0

3 years ago