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2 years ago

17.Which of the following is the equation of a line parallel to y-axis?

Mathematics

1 answer:

AlexFokin [52]2 years ago

7 0

Answer:

I think that the answer is a

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What is 9/11 +2/3 and show the work

erica [24]

Answer:

9/11 = 27/33

2/3 = 22/33

27/33 + 22/33 = 49/33

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Simplfy <br> 2x+4/-3 = 12

nasty-shy [4]

So you have the equation (2x+4)/-3=12
Multiply by -3 on each side.
2x+4=-36
2x=-20
x=-10
Hope this helps.

4 0

3 years ago

Mr.Scott weekly salary is $37 less than Mr. Khanna's. If Scott weekly salary is $584, what is Khanna's weekly salary?

ycow [4]

Answer:

Khannas salary is $547

Step-by-step explanation

Literally all you have to do is subtract 584 by 37.

5 0

3 years ago

Read 2 more answers

Using the simple random sample of weights of women from a data set, we obtain these sample statistics: nequals45 and x overbar

Tomtit [17]

Answer: (141.1, 156.48)

Step-by-step explanation:

Given sample statistics : $n=45$

$\overline{x}=148.79\text{ lb}$

$\sigma=31.37\text{ lb}$

a) We know that the best point estimate of the population mean is the sample mean.

Therefore, the best point estimate of the mean weight of all women = $\mu=148.79\text{ lb}$

b) The confidence interval for the population mean is given by :-

$\mu\ \pm E$ , where E is the margin of error.

Formula for Margin of error :-

$z_{\alpha/2}\times\dfrac{\sigma}{\sqrt{n}}$

Given : Significance level : $\alpha=1-0.90=0.1$

Critical value : $z_{\alpha/2}=z_{0.05}=\pm1.645$

Margin of error : $E=1.645\times\dfrac{31.37}{\sqrt{45}}\approx 7.69$

Now, the 90% confidence interval for the population mean will be :-

$148.79\ \pm\ 7.69 =(148.79-7.69\ ,\ 148.79+7.69)=(141.1,\ 156.48)$

Hence, the 90% confidence interval estimate of the mean weight of all women= (141.1, 156.48)

3 0

3 years ago

A bar of gold has a volume of 722 cubic centimeters and weighs 13.949 kilograms. What's its density in grams per cubic centimete

Ahat [919]

Answer:

The density of the bar of gold is 19.32 grams per cubic centimeter .

Step-by-step explanation:

Formula

$Density = \frac{Mass}{Volume}$

As given

A bar of gold has a volume of 722 cubic centimeters and weighs 13.949 kilograms.

As 1 kilogram = 1000 gram

Than convert 13.949 kilograms into grams.

13.949 kilograms = 13.949 × 1000 grams

= 13949 grams

Mass = 13949 grams

Volume = 722 cubic centimeter

As put in the formula

$Density = \frac{13949}{722}$

Density = 19.32 grams per cubic centimeter (Approx)

Therefore the density of the bar of gold is 19.32 grams per cubic centimeter .

8 0

3 years ago