The E3 is the same as writing 10^3.
The answer would be 7.9 x 10^3
Here are the numbers that represent each based on the box plot:
Median: 11 (located at the vertical line in the middle of the box)
Range: 19 - 7 = 12 (highest value - lowest value)
25%: 9 (at the left end of the box)
75%: 14 (at the right end of the box)
Interquartile range: 14 - 9 = 5 (the distance from the beginning to the end of the middle half of the data)
Answer: 12 + 6b
Step-by-step explanation:
Just times both by 6
Answer:
The test is not significant at 5% level of significance, hence we conclude that there's no variation among the discussion sections.
Step-by-step explanation:
Assumptions:
1. The sampling from the different discussion sections was independent and random.
2. The populations are normal with means and constant variance
There's no variation among the discussion sections
There's variation among the discussion sections

Df Sum Sq Mean sq F value Pr(>F)
Section 7 525.01 75 1.87 0.99986
Residuals 189 7584.11 40.13
Test Statistic = 

Since our p-value is greater than our level of significance (0.05), we do not reject the null hypothesis and conclude that there's no significant variation among the eight discussion sections.
Answer:
x = 11
Step-by-step explanation:
Given the expression;
5x+2y=67 ...1
x=3y−7 ....2
Substitute 2 into 1
5(3y-7)+2y = 67
15y - 35 + 2y = 67
17y = 67+35
17y = 102
y = 102/17
y =6
Recall that x = 3y - 7
x = 3(6) - 7
x = 18 - 7
x = 11
Hence the value of x is 11