Answer:
the picture is kinda blur but nvm
Step-by-step explanation:
3:b
4:b
5:a
6:b
Answer:
k, a, and i I think!
Step-by-step explanation:
The perimeter p of the rectangle with length l and width w is:
p = 2l + 2w
that is, two times its length and two times its width, lets solve for the width w and substitute known data:
<span>p = 2l + 2w
</span>2w = p - 2l
w = (<span>p - 2l</span>)/2
w = (56 - (2*12))/2
w = (56 - 24)/2
w = 32/2
w = 16
therefore the width of the rectangle is 16 in
Area of the rectangle is 2*6=12 in^2
12 could be = 1*12 or 2*6 or 3*4
P could be 2*(1+12)=2*13=26
2*(2+6)=2*8=16
2*(3+4)=2*7=14
the answer is 24 in (c)
11 = w - 12
11 + 12 = w -12 + 12
w = 11 + 12
w = 23
