Step-by-step explanation:










The first answer is the correct one.
It is the only one that keeps all the ratios from the first triangle on the top and the 2nd triangle on the bottom. the other three answers keep swapping top and bottom positions.
According to the markings, BD = DC. From this fact
BD = DC
BD + DC = BC
18 + 18 = BC
BC = 36 <<<<<< Answer
Let's call the height of the tower
and the distance from the 65 degree angle to the base of the tower
.
We get two equations:







Answer: 48
Answer:
C
Step-by-step explanation: