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Elena-2011 [213]
3 years ago
9

4d2e - d2e find difference

Mathematics
2 answers:
Nataliya [291]3 years ago
7 0
I think the answer is 1d.
Tanya [424]3 years ago
4 0
The answer will be: <span>8.154845<span>d^2</span></span>
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can anyone explain this question please - What is the standard form of the following equation? y+3=1/4x Use integers for A, B, a
Vlad1618 [11]
Standard form is
ax+by=c
where a,b,c are integers

y+3=1/4x
timesboth sides by 4
4y+12=x
minus x both sides
-x+4y+12=0
minus 12 both sides
-x+4y=-12
(I like x to be positive so)
times both sides by -1
1x-4y=12
a=1
b=-4
c=12
4 0
3 years ago
The amount A of the radioactive element radium in a sample decays at a rate proportional to the amount of radium present. Given
slavikrds [6]

Answer:

a) \frac{dm}{dt} = -k\cdot m, b) m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }, c) m(t) = 10\cdot e^{-\frac{t}{2438.155} }, d) m(300) \approx 8.842\,g

Step-by-step explanation:

a) Let assume an initial mass m decaying at a constant rate k throughout time, the differential equation is:

\frac{dm}{dt} = -k\cdot m

b) The general solution is found after separating variables and integrating each sides:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }

Where \tau is the time constant and k = \frac{1}{\tau}

c) The time constant is:

\tau = \frac{1690\,yr}{\ln 2}

\tau = 2438.155\,yr

The particular solution of the differential equation is:

m(t) = 10\cdot e^{-\frac{t}{2438.155} }

d) The amount of radium after 300 years is:

m(300) \approx 8.842\,g

4 0
3 years ago
Read 2 more answers
3/2x-2=19 What does x equal?
dimaraw [331]
First, add 2 to both sides. You should have 3/2x=21. Multiply both sides by 2 which gives you 3x= 42. Divide by 3 and you have x=14
4 0
3 years ago
Can someone help me with this problem I really don’t know how to work it out and I’m getting frustrated please help..
11Alexandr11 [23.1K]

Answer:

  1 cake and 6 pies

Step-by-step explanation:

Let c represent the number of cakes Alice and George can make. Likewise, let p represent the number of pies.

Then the amount of flour they need (in cups) is ...

  3c + 2p . . . . cups of flour needed

And the amount of sugar needed is ...

  2c + 1.5p . . . cups of sugar needed

__

They want to use all 15 cups of flour they have, and all 11 cups of sugar, so the amounts above need to match the amounts on hand:

  3c + 2p = 15

  2c + 1.5p = 11

We can solve these equations various ways. One of my favorite is to use a graphing calculator. (See attached) It tells us that Alice and George can make 1 cake and 6 pies with the flour and sugar they have.

_____

If you want to solve these equations algebraically, there are several methods for that, too. Here, we can multiply the first one by 2/3 and subtract the result from the second one:

  (2c +1.5p) -(2/3)(3c +2p) = (11) -(2/3)(15)

  2c +3/2p -2c -4/3p = 11 -10 . . . . . eliminate parentheses

  1/6p = 1 . . . . . . . . . . . . . . . . . . . . . .collect terms

  p = 6 . . . . . . . . . . . . . . . . . . . . . . . . multiply by 6

Substituting into the first equation gives ...

  3c +2·6 = 15 . . . substitute 6 for p

  3c = 3 . . . . . . . . subtract 12

  c = 1 . . . . . . . . . . divide by 3

These values tell us Alice and George can make 1 cake and 6 pies with the flour and sugar they have.

7 0
3 years ago
The value of y varies directly as the square of x and y=36 when x=3. What is y when x=4?
MissTica

Answer: y = 64

Step-by-step explanation:

y <> x² ----------------------- 1

y = kx² ----------------------- 2

36 = 3²k

36 = 9k

K = 36/9

= 4.

To find y when x = 4, we substitute for x in equation 2

y = kx²

y = 4²k

y = 16 x 4

y = 64

6 0
3 years ago
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