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baherus [9]
3 years ago
11

16. PHYSICS The formula h = 1201 - 16t2 gives the height h in feet of an object 1 seconds after it is shot upward from

Mathematics
1 answer:
Murrr4er [49]3 years ago
3 0
<h3><u>Question:</u></h3>

The formula h = 120t-16t^2 gives the height h in feet of an object t seconds after it is shot upward from Earth's surface with an initial velocity of 120 feet per second. What will the height of the object be after 6 seconds?

<h3><u>Answer:</u></h3>

The height of object after 6 seconds is 144 feet

<h3><u>Solution:</u></h3>

<em><u>The formula that gives the height of an object is:</u></em>

h = 120t - 16t^2

Where,

h is the height in feet and t is the time in seconds

To find: height of the object be after 6 seconds

To find the height of the object be after 6 seconds, substitute t = 6

h = 120 \times 6 -16(6)^2\\\\h = 720 - 16 \times 36\\\\h = 720 - 576\\\\h = 144

Thus height of object after 6 seconds is 144 feet

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Tom has 5 comic books in his collections and receives 5 new comic books each month. Joe has 145 comic books, but sends 5 to each
Sindrei [870]

Answer:

In 7 Months both will have same number of comic books.

The both will have 40 comic books in 7 months.

Step-by-step explanation:

Let Number of months be x.

Given:

Tom Has number comic books = 5

Each month he receives number of books = 5

Total Number of books he has after x month can be calculated by sum of number of comic books he has + number of comic books he receives multiplied by number of months

Hence Total Number of books he has after x month = 5+5x

Also Given:

Joe Has number comic books = 145

Each month he send number of books to 1 friend = 5

Number of friends = 3

Hence books send to friend each month = 5\times3 =15

Total Number of books he has after x month can be calculated by Difference of number of comic books he has and number of comic books he send to friends multiplied by number of months

Hence Total Number of books he has after x month = 145-15x

We need to find the number of months in which both will have same number of of comic book.

Hence we can find by making both equation equal we get;

5+5x=145-15x

Combining same terms we get;

5x+15x=145-5\\20x =140\\x=\frac{140}{20}=7 \ months

Hence the will have same number of comic books after 7 months.

Now we need to find the number of books the both had after 7 months:

Tom has = 5+5x=5+5\times7= 5+35=40\ books

Joe has = 145 - 15x = 145 - 15\times7 = 145-105 = 40 \ books

Hence they both will have 40 comic books after 7 months.

4 0
3 years ago
You have 3 online accounts in three different banks valued at: bank "A" = $250.67, 12% interest, bank "B" $765.13, 7% interest,
gregori [183]

Answer:

\$882.89

Step-by-step explanation:

we know that

The simple interest formula is equal to

I=P(rt)

where

I is the Final Interest Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have

Bank A

t=1\ years\\ P=\$250.67\\r=12\%=12/100=0.12

substitute in the formula above

I=250.67(0.12*1)=\$30.08

Bank B

t=1\ years\\ P=\$765.13\\r=7\%=7/100=0.07

substitute in the formula above

I=765.13(0.07*1)=\$53.56

Bank C

t=1\ years\\ P=\$28,500.36\\r=9\%=9/100=0.09

substitute in the formula above

I=28,500.36(0.09*1)=\$2,565.03

Find the average interest gained from the three accounts in one year

[\$30.08+\$53.56+\$2,565.03]/3=\$882.89

3 0
3 years ago
HELP ASAP THIS DUE TODAY FOR MY BRO
Harman [31]

Answer:

I think it's 10 or 10.5 not sure

Step-by-step explanation:

4 0
2 years ago
Write 720,080 in expanded form with exponents
disa [49]
Why are you having us do your homework 
7 0
3 years ago
Read 2 more answers
Delta makes 12-volt car batteries. These batteries are known to be normally
blondinia [14]

Answer:

The probability that Delta car batteries last between three and four years

P(36≤X≤48) = 0.5188

The percentage of that Delta car batteries last between three and four years

P(3≤X≤4) = 52%

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given that the sample size n =12 -volt car batteries</em>

<em>Let  'X' be a Random variable in a normal distribution</em>

<em>Given that mean of the normal distribution = 45 months</em>

<em>Given that the Standard deviation of the normal distribution = 8months</em>

<u><em>Step(ii):-</em></u>

Let  X₁ = 3 years = 12 × 3 = 36 months

Z_{1} = \frac{x_{1} -mean}{S.D} = \frac{36-45}{8} = -1.125

Let X₂ = 4 years  = 12 × 4 = 48 months

Z_{2} = \frac{x_{2} -mean}{S.D} = \frac{48-45}{8} = 0.375

<u><em>Step(iii)</em></u>:-

The probability that Delta car batteries last between three and four years

P(36≤X≤48) = P(-1.125≤Z≤0.375)

                   = P(Z≤0.375) - P(Z≤-1.125)

                   = 0.5 +A(0.375) - (0.5-A(1.125)

                   = 0.5 + 0.1480 - (0.5 -0.3708)

                  = 0.1480 + 0.3708

                 = 0.5188

<u><em>Final answer:-</em></u>

The probability that Delta car batteries last between three and four years

P(36≤X≤48) = 0.5188

The percentage of that Delta car batteries last between three and four years

P(3≤X≤4) = 52%

<em />

5 0
3 years ago
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