I believe the answer is 5y :)
Answer:
and
.
Step-by-step explanation:
So I believe the problem is this:

where we are asked to find values for
and
such that the equation holds for any
in the equation's domain.
So I'm actually going to get rid of any domain restrictions by multiplying both sides by (x-3)(x+7).
In other words this will clear the fractions.


As you can see there was some cancellation.
I'm going to plug in -7 for x because x+7 becomes 0 then.




Divide both sides by -10:


Now we have:
with 
I notice that x-3 is 0 when x=3. So I'm going to replace x with 3.




Divide both sides by 10:


So
and
.
Input each points. (x,y) for each equation to find out if the system of equations are equivalent.
Point (-3,4) is a solution of this system of equations.
Point (-2,-6) isn't a solution of this system of equations.
Point (-4,3) is a solution of this system of equations.
First you need to know the definition of a complementary angle. That means that two angles add up to 90 degrees, or a right angle.
To find an angle complementary to a 78 degree angle, you need to subtract 78 from 90.
90 - 78 = 12
Hello,
"T<span>he product of 8 and a number increased by 4" may be understood by 2 ways:
1) it is the number which is increased
2) it is the product which is increased.
1) 8*(y+4) =8y+32
2) (8y)+4=8y+4
Seeing answers
:answer A: 8y+4
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