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slava [35]
3 years ago
9

How many moles of Al(CN)3 are in 183 g of the compound?

Chemistry
1 answer:
Lyrx [107]3 years ago
4 0
You need to calculate the molar mass for Al(CN)3 using the atomic weights for Al, C, and N given on the periodic table.

1 Al (26.98) + 3 C (3 x 12.01) + 3 N (3 x 14.01) = 105.04 g Al(CN)3 / mole

183 g Al(CN)3 x (1 mole Al(CN)3 / 105.04 g Al(CN)3) = 1.74 moles Al(CN)3
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Explanation:

A.

Yes

B.

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C.

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D.

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1 mole of Ba(OH)2 reacted with 2 moles of KHP. By stoichiometry,

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= 0.00125 mol.

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Explanation:

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