Answer: 122.5088
Explanation:
1 mole of H2O = 2(1.008)+1(16) = 18.016
6.8 moles of H2O = 6.8×18.016 = 122.5088
Answer is: <span>the molecular mass ratio of two gases is 1 : 256.
</span>rate of effusion of
gas1 : rate of effusion of gas = 16 : 1.<span>
rate of effusion of gas1 = 1/√M(gas1).
rate of effusion of gas2 = 1/√M(gas2).
rate of effusion of gas1 = rate of
effusion of gas2 </span>· 16<span>.
</span>1/√M(gas1) = 1/√M(gas2) · 16 /².
<span>1/M(gas1) = 1/M(gas2) </span>· 256.
<span>M(gas1) </span>· 256 = M(gas2).<span>
</span>
Answer: 2.04L
Explanation:
coldest temperature = -10°C
mass of solvent = 6.50kg
freezing point depression = kb*m
Where kb = molar freezing point depression constant, 1.86
10 = 1.86 * molality of ethylene glycol
10 = 1.86 * moles of ethylene glycol/mass of solvent
10 = 1.86 * moles of ethylene glycol/6.5
10*6.5 = 1.86 * moles of ethylene glycol
Moles of ethylene glycol = 65/1.86
Moles of ethylene glycol = 36.11
36.11 mol * 62.1 g/mol = 2242.43g = 2.24kg
1 L = 1000 mL x 1.11 g/mL = 1100 g = 1.1 kg
2.24 kg / 1.10 kg/L = 2.04 L
7.5x10^14 Hz. I just worked it out on paper.
