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BARSIC [14]
3 years ago
15

When you apply for a scholarship, you may have to write an application essay?

Mathematics
2 answers:
Anna [14]3 years ago
7 0

Answer your answer is b

Step-by-step explanation:

to show that you have the writing skills in order to succeed in college

Charra [1.4K]3 years ago
3 0

Answer: I believe it's B. to show that you have the writing skills in order to succeed in college.

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Genghis Khan organized his men into groups of 10 soldiers under a "leader of 10." Ten "leaders of 10" were under a "leader of 10
Drupady [299]

Answer:

(a) 11110 soldiers

(b) 6404 soldiers

Step-by-step explanation:

Following that logic you can express the men of any level of his organization as 10^n, where n is the level. Some examples:

Level 1: 10^1 = 10

Level 2: 10^2 = 100 Each of the 10 men in level 1 are in charge of 10 men in the level 2 (10 * 10 = 100)

(a) if the lowerst level of the organization has 10,000 soldiers, then the lowest level is:

10^n = 10,000

n = 4

The total number of men under him is:

10^4+10^3+10^2+10^1 = 11110 (Assuming that he is the leader of the first 10 leaders)

(b) In this case the lowest level has 5763, you have a 1 leader for every 10 soldiers, then the leaders needed for the lowest level is:

5763/ 10 = 576.3 = 577 leaders

These 577 leaders also have their own leaders for every 10:

577/10 = 57.7 = 58 leaders

And these also have their own leaders:

58 / 10 = 5.8 = 6

And again We assume these 6 are directly under Genghis Khan

Total soldiers:

5763 + 577 + 58 + 6 = 6404 soldiers

6 0
3 years ago
PLZ HELP WILL MARK BRAINLIEST!
goblinko [34]

Step-by-step explanation:

directrix = (1, -1)

focus = (-3, 2)

vertex = (-3, 3)

7 0
2 years ago
'Polonium-210 is a radioactive substance with a half-life of 138 days. If a nuclear
Tatiana [17]

Answer:

  • <u>59.0891 g (rounded to 4 decimal places)</u>

Explanation:

<em>Half-life time</em> of a radioactive substance is the time for half of the substance to decay.

Thus, the amount of the radioactive substance that remains after a number n of half-lives is given by:

  • A=A_0\cdot (1/2)^n

Where:

  • A is the amount that remains of the substance after n half-lives have elapses, and
  • A₀ is the starting amount of the substance.

In this problem, you have that the half-live for your sample (polonium-210) is 138 days and the number of days elapsed is 330 days. Thus, the number of half-lives elapsed is:

  • 330 days / 138 days = 2.3913

Therefore, the amount of polonium-210 that will be left in 330 days is:

  • A=310{g}\cdot (1/2)^{2.3913}=59.0891g
5 0
3 years ago
Change 0.61 into a fraction
stiks02 [169]
The answer to your question is 61/99
3 0
3 years ago
Read 2 more answers
Twelve of the 20 students in Ms. Sarno’s homeroom are female. Each month, Ms. Sarno randomly selects a student to act as “teache
Ksivusya [100]

Answer:

C. A bag of 15 marbles , with 9 marbles representing female students, has a marble drawn 4 times with replacement

Step-by-step explanation:

i took the test and got it right ;)

3 0
3 years ago
Read 2 more answers
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