Outcomes for what tho exactly?
Answer:
<u>There are:</u>
- 6 red balls - R
- 5 black balls - B
- Total number = 11 balls
<h3>A. Without replacement</h3>
i. <u>Two blacks </u>
ii. <u>The first is black</u>
or, alternatively
- P(BR or BB) = 5/11*6/10 + 2/11 = 3/11 + 2/11 = 5/11
iii. <u>Both are of same colour</u>
- P(BB or RR) = 2/11 + 6/11*5/10 = 2/11 + 3/11 = 5/11
<h3>B. With replacement</h3>
i. <u>Two blacks </u>
- P(BB) = 5/11*5/11 = 25/121
ii. <u>The first is black</u>
or alternatively
- P(BR or BB) = 5/11*6/11 + 25/121 = 30/121 + 25/121 = 55/121 = 5/11
iii. <u>Both are of same colour</u>
- P(BB or RR) = 5/11*5/11 + 6/11*6/11 = 25/121 + 36/121 = 61/121
Answer:
f(x)=start fraction 4 over x squared End fraction minus start fraction 2 over x end fraction +1
Here we are given the three sides of the triangle.
So we have Heron's formula to find its area.
Heron's formula is given by :
where A, B and C are sides of triangle and S is semi perimeter which is given by,
plugging values of A, B and C to find S
S=13.5
Now plugging values of A, B , C and S in Heron's formula
A=26.14 mm²
Answer: Area of triangle is 26.14 mm².