$\log_2 (\log_5( \log_3x)) = 0\\
D:x>0 \wedge \log_3x>0 \wedge \log_5(\log_3x)>0\\
D:x>0\wedge x>1 \wedge\log_3x>1\\
D:x>1 \wedge x>3\\
D:x>3\\
\log_5(\log_3x)=1\\
\log_3x=5\\
x=3^5\\
x=243$

3 0

3 years ago

James was saving his money to buy a new bicycle. The bicycle originally costs $150 but then the store owner marked up its price

Volgvan

Answer:

$180

Step-by-step explanation:

To find the new cost, multiply the original cost by 1.2

150(1.2)

= 180

So, the new cost of the bicycle is $180

5 0

3 years ago

Read 2 more answers

The measure of angle A is 15°, and the length of side

dangina [55]

Answer:

Part 1) $AB=30.9\ units$

Part 2) $AC=29.9\ units$

Step-by-step explanation:

The picture of the question in the attached figure

Part 1

Find the length side AB

we know that

$sin(A)=\frac{BC}{AB}$ ----> by SOH (opposite side divided by the hypotenuse)

substitute the given values

$sin(15^o)=\frac{8}{AB}$

solve for AB

$AB=\frac{8}{sin(15^o)}=30.9\ units$

Part 2

Find the length side AC

we know that

$tan(A)=\frac{BC}{AC}$ ----> by TOA (opposite side divided by the adjacent side)

substitute the given values

$tan(15^o)=\frac{8}{AC}$

solve for AC

$AC=\frac{8}{tan(15^o)}=29.9\ units$

8 0

3 years ago

Can i get some on these please?^^​

Can i get some on these please?^^