Cant really see it like that
Answer:
m∠GKH = m∠JKI Subtraction Property
Step-by-step explanation:
Given:
Line GI intersects line JH at point K. The proof of ∠GKH ≅ ∠JKI is shown.
To complete the 5th step in the proof.
Solution:
In order to prove ∠GKH ≅ ∠JKI , we need to first show that m∠GKH = m∠JKI .
We can use properties of equality to prove it.
4th Step is as follows :
Using subtraction property:
Subtracting both sides by m∠HKI
Thus, we have the 5th step as:
The center of a circle whose equation is x^2 +y^2 – 12x – 2y +12 = 0 is (6,1)
<h3>Equation of a circle</h3>
The standard equation of a circle is expressed as:
x^2 + y^2 + 2gx + 2fy + c = 0
where:
(-g, -f) is the centre of the circle
Given the equations
x^2 +y^2 – 12x – 2y +12 = 0
Compare
2gx = -12x
g = -6
Simiarly
-2y = 2fy
f = -1
Centre = (6, 1)
Hence the center of a circle whose equation is x^2 +y^2 – 12x – 2y +12 = 0 is (6,1)
Learn more on equation of a circle here: brainly.com/question/1506955
Answer is probably Number 1.
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