No, because the size of their respective dimensions are not proportional
The general formula: y=mx+b
(6,2) ⇒ x=6,y=2
m=3
b=?
2=3*6+b
2=18+b
b=-16
<u>y=3m-16</u>
Answer:
3/4 ÷ 1/2
Step-by-step explanation:
He first two are relatively easy. f(x-2) shifts it sideways (2 to the right in this case) f(x) -2 shifts it straight down (by 2)
f(2x) means replace x with 2x in the original 4(2x + 1)^2 − 3 if you factor out the 2 from the square root you get 4*sqr(2) ( x + ½)^2 - 3 which is now in the form a ( x -h)^2 + k the vertex is now at (-½, -3) (it used to be at (-1,-3) the "a" has gotten bigger, which makes the parabola "skinnier" (it goes up faster)
2•f(x) becomes 2*( 4(x + 1)2 − 3 ) = 8 (x+1)^2 -6 where is the vertex now? is this parabola fatter or skinnier than the original f(x) ?