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3 years ago

At lunchtime 5/6 of students buy juice. Of those students 3/4 buy orange juice. What fraction of the students buy orange juice?

Mathematics

1 answer:

IrinaK [193]3 years ago

7 0

5/6 × 3/4

=5/2 × 1/4

=5/8

Answer

5/8 students buy orange juice

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6. (08.02 MC)

MariettaO [177]

Answer:

The percentage change in volume between cylinder A and cylinder B is 50%

Step-by-step explanation:

The volume of a cylinder is given by the formula

V= πr^2h

For cylinder A, where r=7 and h= 5, π=22/7

V= π * 7^2 * 5

V= π * 49 * 5

V= 769.69 cubic inch

For cylinder B

V= 490π

V= 1539.3804 cubic inch

The percentage change in volume between cylinder A and cylinder B

=[ (VA- VB)/VB] *100

=( 1539.3804 - 769.69) / 1539.3804

= 0.5000 * 100

= 50%

8 0

3 years ago

ASAP PLEASE HELP AND EXPLAIN TOO!!!!!!

VARVARA [1.3K]

Looking at number 4, you first have to look at the information that you have:
On tuesday he practiced for 1 5/6 hrs
Monday he practiced for 7/10 hrs
He is supposed to practice for 1 1/4 hr.
You could write questions like:
How much more did Marco practice on Tuesday than he is supposed to practice?
This works because it does indeed involve subtraction, you would be subtracting the amount that he should have practiced from the amount of time that he did practice.
If I didn't answer the question, please message me and I will clarify!

6 0

3 years ago

Find the perimeter of the object Help step by step please!

aliina [53]

Answer:

29.42 units

Step-by-step explanation:

1) Find the perimeter around the semi-circle

To do this, we find the circumference of the circle using the given diameter:

$C=\pi d$ where d is the diameter

Plug in 6 as the diameter

$C=\pi (6)\\C=6\pi$

Divide the circumference by 2

$\frac{6\pi }{2} \\= 3\pi$

Therefore, the perimeter around the semi-circle is 3π units.

2) Find the perimeter around the rest of the shape

Although it's impossible to determine the lengths of the varied sides on the right side of the shape, we know that all of those vertical sides facing the right add up to 6. We also know that all of those horizontal sides facing up add up to 7. Please refer to the attached images.

Therefore, we add the following:

7+6+7

= 20

Therefore, the perimeter around that area of the shape is 20 units.

3) Add the perimeter around the semi-circle and the perimeter around the rest of the shape

$20+3\pi \\= 20+9.42\\= 29.42$