¿Qué efecto tendrá un macho la extirpación de uno de sus testículos?

Biology

1 answer:

ivann1987 [24]3 years ago

8 0

Answer:

Perder un testículo usualmente no tiene ningún efecto en la capacidad de un hombre de lograr una erección y tener sexo. No obstante, si se extirpan ambos testículos, no se pueden producir espermatozoides y el hombre queda estéril.

Explanation:

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The act of breathing raises the blood oxygen level, lowers the blood carbon dioxide concentration, and raises the blood pH. Acco

tino4ka555 [31]

Answer:

A rise in blood carbon dioxide concentration.

Explanation:

The feedback regulation may be defined as the process in which the end product of the metabolic pathway regulates the homeostasis of the body. Two main types of feedback are positive feedback and negative feedback.

The negative feedback mechanism occurs when the end product of the reaction is responsible for the shutdown of the metabolic pathway and decreases its concentration. The breathing is controlled by the negative feedback mechanisms, the increase in carbon dioxide concentration acts as the negative sensor as this sensor is mainly responsible for the increase in amount of oxygen level and maintain homeostasis of the body.

Thus, the correct answer is option (c).

6 0

3 years ago

A population of 100 tigers has 30 with horizontal stripes. Using pedigrees, you ascertain that horizontal striping is caused by

bixtya [17]

Assuming that this population is in Hardy-Weinberg equilibrium, we can sayt that the probability that, given enough time, all tigers in the population will have horizontal stripes is 30% = 0.3.

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Available data:

Population size, N = 100 tigers
Number of Tigers with horizontal stripes = 30
Horizontal stripes is caused by an autosomal recessive mutation.

We need to know the probability that all tigers in the population will have horizontal stripes, which is the recessive phenotype.

We assume that the population is in Hardy-Weinberg equilibrium, so there should be no evolution.

Since the population is in H-W equilibrium, the allelic, genotypic and phenotypic frequencies will remain the same generation after generation.

Now, we will calculate the allelic and genotypic frequencies of horizontal striped individuals in the population.

There are 100 individuals, and only 30 have horizontal stripes.

So, the phenotypic frequency, F(HS) is 30/100 = 0.3 = 30%

Since this is a recessive phenotype, this value equals the genotypic frequency, F(hh) = 30%

Finally, we can get the allelic frequency by taking the square root of this value.

F(hh) = q² = 0.3

f(h) = q = √0.3 = 0.55 = 55%

According to these calcs, the probability for the fixation of the recessive allele is 55%, and the probability that all individuals express the recessive horizontal stripes phenotype is 30%.

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You can learn more about Hardy-Weinberg equilibrium at

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6 0

3 years ago

PLEASE HELP!!! EMERGENCY!!!

Ipatiy [6.2K]

it would be C because kingdom is animalia, phylum is chordata, class is mammalia and order is carnivora and humans and tigers are both carnivors