The solution to the system of equation is (2, 7)
<h3>System of equation</h3>
Given the system of equation expressed as:
3x – y = -1 * 2
x – 2y = -12 * 1
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6x – 2y = -2
x – 2y = -12
Subtract to have;
6x-x = -2-(-12)
5x = 10
x = 2
Substitute x = 2 into 2 to have:
2 - 2y = -12
-2y = -14
y = 7
Hence the solution to the system of equation is (2, 7)
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I think x=9 so 29 plus 7 is 36. I think it is a 36 degree angle. Correct me if im wrong
After plotting all the three points, we get the parabolic equation in the form is 2(x - 1)²-34.
<h3>What is parabola?</h3>
Any point on a parabola, which has the shape of a U, is situated at an equal distance from the focus, a fixed point, and the directrix, a fixed line.
General equation of the quadratic equation,
Y = ax² + bx +c
Given points,
(-2, 0),
(-1, -10),
(4, 0).
Putting the points in the general equation,
Putting (-2, 0), we get
0 = 4a - 2b + c
Putting (-1, -10), we get
-10 = a - b +c
Putting (4, 0), we get
0 = 16a + 4b +c
Solving all equations we get,
a = 2 , b = -4 , c = -16
After putting the values,
Y = 2x²- 4x- 16
2(x² - 2x - 8)
2(x²- 2x + 1 - 1 - 16)
=2(x - 1)²-34
Hence we get the required equation in the parabolic form.
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Answer:
y = 3/2*x - 5
Step-by-step explanation:
Lets say that P1=(6,4) and P2=(4,1) and that the form of the equation must be y=m*x+b where m is the slope and b the independent variable. Then having two given points we can use the slope formula to find the slope value as:
P1=(x1,y1) and P2=(x2,y2)
slope formula ---> m=(y2-y1)/(x2-x1)
Replacing the given points ---> m=(1-4)/(4-6) = 3/2
then replacing the slope value obtained:
y = 3/2*x + b
Now lets find the value of b. For this we have to replace in the equation a point it can be P1 or P2, i will replace P2:
1 = 3/2*4 + b
1 = 6 + b
1 - 6 = b
-5 = b
therefore the line equation is:
y = 3/2*x - 5
