Bob cannot distribute the cups in six equal stacks and not have any left over.
Step-by-step explanation:
In order to divide the total number of cups in six equal stacks with no left over, the total number of cups will be divided by 6, if there is any remainder then the cups cannot be equally divided with no left over.
So
Dividing 64 by 6
Here
Quotient = 10
Remainder = 4
As there are 4 cups left, Bob cannot distribute the cups in six equal stacks and not have any left over.
Keywords: Division, fractions
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Answer:
Step-by-step explanation:
Carter rode his bike 9/10 of a mile from his house to his grandmothers house. This means that the distance from Carter's house to his grandmother's house is 0.9 miles. On his way back home, he rode 3/8 of a mile before the tyre on his bike went flat. This means that he rode 0.375 miles before his tyre went flat. The distance he must walk before he gets home will be the total distance from home minus the distance that he rode. It becomes
0.9 - 0.375 = 0.575 miles
Answer:
x - 99 ≤ -104 → 2nd line
x - 51 ≤ -43 → 1st line
150 + x ≤ 144 → 4th line
75 < 69 - x → 3rd line
Step-by-step explanation:
Ugh! Wow, this is going to be tedious, thanks alot, bro (jk, I got your back).
x - 99 ≤ -104
+ 99 + 99
x ≤ -5
There should be a line going from -5 to negative infinity (AKA the left) with a FILLED circle. So, the second one is correct.
x - 51 ≤ -43
+ 51 + 51
x ≤ 8
There should be an arrow with a FILLED circle going to negative infinity (AKA the left). So, the first one is correct.
I'm going to take a shortcut and notice that one of the lines has a filled circle while the other one has an empty circle. So the empty circle must relate to the question without a ≤ or ≥, but with a < or >. We see that 75 < 69 doesn't have ≤ or ≥ but a '<.' So this one must have the empty circle, which is on line 3. The last equation has to be on line 4.
Answer:
The solutions are linearly independent because the Wronskian is not equal to 0 for all x.
The value of the Wronskian is 
Step-by-step explanation:
We can calculate the Wronskian using the fundamental solutions that we are provided and their corresponding the derivatives, since the Wroskian is defined as the following determinant.
Thus replacing the functions of the exercise we get:
Working with the determinant we get
Thus we have found that the Wronskian is not 0, so the solutions are linearly independent.
