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xxMikexx [17]
3 years ago
11

Solve the following system y=-2 -2x-7y=24

Mathematics
1 answer:
Dafna1 [17]3 years ago
6 0

Answer:

x = -5

y = -2

Step-by-step explanation:

<em><u>Since you have y, plug that into the equation:</u></em>

-2x - 7y = 24

-2x - 7(-2) = 24

-2x + 14 = 24

<u><em>Then, subtract 14 from both sides:</em></u>

-2x + 14 = 24

      - 14   - 14

__________

-2x = 10

<u><em>Finally, divide both sides by -2:</em></u>

-2x = 10

x = -5

So now you have, x = -5 and y = -2.

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C. Tasha's balloon was farther from the town at the beginning but, Henry's balloon traveled more quickly.

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
Please help confused with half life /compound interest problems
jekas [21]
Half life means only half of matter is left, which means half is decayed/radiated. 
Formula for half life is
t/2 = [(elapsed time)*(log2)]/[log(beginning amount/ending amount)]
1. t/2 = [(10)*(log2)]/[log(100/76.1)] = 25.378 minutes.
 t/2 = [10 * 0.301]/[log 1.314] = [3.01]/[0.1186] = 25.378
2. 53.12 = [(T)*(log2)]/[log(15/4)], on solving we get, T = 101.29 days
 53.12 = [T * 0.301]/[log 3.75] = [0.301 * T]/[0.574],
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6 0
3 years ago
Suppose that prices of a certain model of a new home are normally distributed with a mean of $150,000. Use the 68-95-99.7 rule t
levacccp [35]

Answer:

68% of buyers paid between $147,700 and $152,300.

Step-by-step explanation:

We are given that prices of a certain model of a new home are normally distributed with a mean of $150,000.

Use the 68-95-99.7 rule to find the percentage of buyers who paid between $147,700 and $152,300 if the standard deviation is $2300.

<u><em>Let X = prices of a certain model of a new home</em></u>

SO, X ~ Normal(\mu=150,000 ,\sigma=2,300)

The z score probability distribution for normal distribution is given by;

                             Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean price = $150,000

            \sigma = standard deviation = $2,300

<u>Now, according to 68-95-99.7 rule;</u>

Around 68% of the values in a normal distribution lies between \mu-\sigma and \mu-\sigma.

Around 95% of the values occur between \mu-2\sigma and \mu+2\sigma .

Around 99.7% of the values occur between \mu-3\sigma and \mu+3\sigma.

So, firstly we will find the z scores for both the values given;

         Z  =  \frac{X-\mu}{\sigma}  =  \frac{147,700-150,000}{2,300}  = -1

         Z  =  \frac{X-\mu}{\sigma}  =  \frac{152,300-150,000}{2,300}  = 1

This indicates that we are in the category of between \mu-\sigma and \mu-\sigma.

SO, this represents that percentage of buyers who paid between $147,700 and $152,300 is 68%.

7 0
3 years ago
36a^2+24b^2=12( +2b^2)
vlabodo [156]
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To get to this answer you need to
1. divide the both sides of the equation by 12.
2. subtract 2b^2 from both sides. 
You will see that the blank space equals 3a<span>^2 then</span>
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3 years ago
Allan bought a rug shaped as a semicircle that has a radius of 4 yards. What is the circumference of the rug? Plz answer
pentagon [3]
Circumference = 2 x pi x radius

2 x pi x 4 = 25.13 yards
(correct to 2 decimal places)

Hope this helps!!
3 0
3 years ago
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