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xxMikexx [17]
3 years ago
11

Solve the following system y=-2 -2x-7y=24

Mathematics
1 answer:
Dafna1 [17]3 years ago
6 0

Answer:

x = -5

y = -2

Step-by-step explanation:

<em><u>Since you have y, plug that into the equation:</u></em>

-2x - 7y = 24

-2x - 7(-2) = 24

-2x + 14 = 24

<u><em>Then, subtract 14 from both sides:</em></u>

-2x + 14 = 24

      - 14   - 14

__________

-2x = 10

<u><em>Finally, divide both sides by -2:</em></u>

-2x = 10

x = -5

So now you have, x = -5 and y = -2.

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-7/4 < -2/3 < 0 < 0.6 < 3/4 < 3

Step-by-step explanation:

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3 years ago
Blake's bedroom is 12 feet long and 5 feet wide he plans to purchase carpet for the entire room the carpet cost $25 per square m
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Write 36% as a simplest fraction
solniwko [45]

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2 years ago
The head of the Westlane Cultural Center wants to get a sense of how quickly pledges from donors arrive at the center. It takes
Rzqust [24]

Answer:

95.64% probability that pledges are received within 40 days

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 28, \sigma = 7

What is the probability that pledges are received within 40 days

This is the pvalue of Z when X = 40. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{40 - 28}{7}

Z = 1.71

Z = 1.71 has a pvalue of 0.9564

95.64% probability that pledges are received within 40 days

7 0
4 years ago
Kala’s company makes solid metal balls for various industrial uses. A customer wants aluminum balls that have a diameter of 6 in
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7,912.8 inch³ of aluminum is needed to make 70 metal balls.

Step-by-step explanation:

Step 1:

The area of a sphere is calculated by multiplying \frac{4}{3} with π and the cube of the radius (r³).

In the given problem, the diameter is 6 inches. So the radius of the spheres is 3 inches.

The volume of a sphere,V = \frac{4}{3} \pi r^{3} .

So if r = 3 inches and π = 3.14,  

V = \frac{4}{3} (3.14) (3^{3})  = 113.04 cubic inches.

So for a single aluminum ball, 113.04 inch³ of aluminum is needed.

Step 2:

If 113.04 inch³ of aluminum is used for 1 ball, then we multiply 70 with this value to determine the aluminum needed for 70 such balls.

The aluminum needed for 70 metal balls = 70(113.04) = 7,912.8 inch³.

So 7,912.8 inch³ of aluminum is needed to make 70 metal balls.

7 0
4 years ago
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