I FOUND YOUR COMPLETE QUESTION IN OTHER SOURCES.
PLEASE SEE ATTACHED IMAGE.
For this case what you should do is use the following trigonometric relationship:
sine (theta) = C.O / h
Where,
theta: angle
C.O: opposite leg
h: hypotenuse
Substituting values we have:
sine (80) = 9 / x
Answer:
sine (80) = 9 / x
First we know that:
AB+BC=AC
now , since B is the midpoint of AC, this means that AB=BC
therefore,
AB+BC=AC can also be written as
AB+AB=AC
3x-1+3x-1=8x-20
6x-2=8x-20
-2+20=8x-6x
18=2x
x=9
therefore:
AB=3(9)-1=27-1=26
AC=8(9)-20=52
BC=AB=26
1/67 maybe -------------------