Answer:
The first five terms of the given sequence
3, 6, 11, 18, 27
Step-by-step explanation:
It is given that,
an=n² +2
<u>To find the first five terms</u>
a₁ = 1² + 2 = 1 + 2 = 3
a₂ = 2² + 2 = 4 + 2 = 6
a₃ = 3² + 2 = 9 + 2 = 11
a₄ = 4² + 2 = 16 + 8 = 18
a₅ = 5² + 2 = 25 + 2 = 27
Therefore the first five terms of the given sequence
3, 6, 11, 18, 27
Answer:
4.47100222
Step-by-step explanation:
157/2.5=62.8
62.8/pi= 19.98986085
square root the answer above and you get 4.47100222 for the radius
4). x/5 =8
x = 40
5). 2x/3 = 12
2x = 36
x = 36/2 = 18
6). x + 26 =12
x = 12 - 26 = -14
7). 8x + 1 = -23
8x = -23 -1
8x = -24
x = -24/8 = -3
8). 2x + 5 =15
2x = 15 - 5
2x = 10
x = 10/2 = 5
9). 3x - 1 = -29
3x = -29 + 1
3x = -28
x = -28/3 Or 9.33
10). 8x - 12 = 53
8x = 53 + 12
8x = 65
x = 65/8 Or 8.12
11). 4x + 7 = 25
4x = 25 - 7
4x = 18
x =18/4 = 9/2 Or 4.5
