The expression for (r-s)(x) is found by subtracting s from r. That difference is
. The expression for (r+s)(x) is found by adding them, which is
. Now we are told to evaluate (r*s)(x) which means they want us to multiply those and state the "new" expression that results.
. There you go!
The answer is 25:1 or 25 to 1. They are the same thing thought.
10x - 12 + 10 = 18 - 20
10x - 2 = -2
10x = 0
x = 0
The system of equations can be used to determine how much of product x and product y the store owner bought is x + y = 4,000
0.10x + 0.04y = 352
<h3>Simultaneous equation</h3>
- product x
- Product y
- Total units of x and y = 4,000 units
- Cost of shipping each product x = $0.10
- Cost of shipping each product y = $0.04
- Total cost of shipping = $352
The equation:
x + y = 4,000
0.10x + 0.04y = 352
Therefore, the system of equations can be used to determine how much of product x and product y the store owner bought is x + y = 4,000
0.10x + 0.04y = 352
Learn more about simultaneous equation:
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Answer: Since the second differences are constant, there is a quadratic relationship between and .
Step-by-step explanation:
