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Snowcat [4.5K]
3 years ago
8

The number of lines of reflection about which the combined figure can reflect onto itself is ____

Mathematics
1 answer:
Fiesta28 [93]3 years ago
7 0
A square(hope it helps)
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Use the law of cosines to find the indicated missing side
max2010maxim [7]

Answer:

19.08

Step-by-step explanation:

c² = a² + b² - 2ab×cos(C)

a=10

b=22

C=60

cos(60) = 0.5

c² = 10² + 22² - 2×10×22×cos(60) =

= 100 + 484 - 20×22×0.5 = 584 - 20×11 = 584 - 220 =

= 364

c = sqrt(364) ≈ 19.08

7 0
3 years ago
PLS HELP ASAP! GIVING BRAINLIST!
Rus_ich [418]

Answer:

I think it is 8, i did not learn this in school

Step-by-step explanation:

2(3x^2+5)

6x^2+10

7 0
3 years ago
Please help me in this. I need to turn this assignment in!
olga2289 [7]

Answer:

X-----Independent Variable

Y-----Dependent Variable

Dependent Variable-----A variable whose value determines the value of the output

Independent Variable-----A variable whose value determines the value of the input

Input-----The value substituted into an expression or function

Output----The value that results from the substitution of a given input into an expression or function

4 0
2 years ago
Can someone explain this??
alexandr402 [8]

Answer:

Step-by-step explanation:

a+(n-1)*d=t_{n}\\\\a+(70-1)*(-43)=t_{70}\\\\a+69*(-43)=500\\\\a-2967=500\\\\a=500+2967\\\\a=3467

4 0
3 years ago
If the coordinates of the endpoints of a diameter of the circle are​ known, the equation of a circle can be found.​ First, find
Evgesh-ka [11]

Answer:

The equation of the circle is (x+3)^2+(y-5)^2 = 17

Step-by-step explanation:

The complete question is

If the coordinates of the endpoints of a diameter of the circle are​ known, the equation of a circle can be found.​ First, find the midpoint of the​ diameter, which is the center of the circle. Then find the​ radius, which is the distance from the center to either endpoint of the diameter. Finally use the​ center-radius form to find the equation.

Find the center-radius  form of the circle having the points (1,4) and (-7,6) as the endpoints of a diameter.

Consider that, if both points are the endpoints of a diameter, the center of the circle is the point that is exactly in the middle of the two points (that is, the point whose distance to each point is equal). Given points (a,b) and (c,d), by using the distance formula, you can check that the middle point is the average of the coordinates. Hence, the center of the circle is given by

(\frac{1-7}{2}, \frac{4+6}{2}) = (-3,5).

We will find the radius. Recall that the radius of the circle is the distance from one point of the circle to the center. Recall that the distance between points (a,b) and (c,d) is given by \sqrt[]{(a-c)^2+(b-d)^2}. So, let us use (1,4) to calculate the radius.

r = \sqrt[]{(1-(-3))^2+(4-5)^2} = \sqrt[]{17}.

REcall that given a point (x_0,y_0). The equation of a circle centered at the point (x_0,y_0) is

(x-x_0)^2+(y-y_0)^2 = r^2

In our case, (x_0,y_0)=(-3,5) and r=\sqrt[]{17}. Then, the equation is

(x-(-3))^2+(y-5)^2 = (x+3)^2+(y-5)^2 = 17

4 0
3 years ago
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