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Tresset [83]
3 years ago
15

HELP FAST 5√6 As a Whole Radical

Mathematics
2 answers:
slega [8]3 years ago
8 0

Answer:

sqrt(150)

Step-by-step explanation:

We want to write the whole number inside the radical

5 = sqrt(5*5)

We know that sqrt(a) sqrt(b) = sqrt(ab)

5 * sqrt(6)

sqrt(5*5) * sqrt(6)

sqrt(5*5*6)

sqrt(150)

Lelechka [254]3 years ago
3 0

Answer:

\sqrt{150}

Step-by-step explanation:

since the 5 is out of the sqrt root, you need to ^2 to put it back in again.

5^{2}=25

and then in the sqrt you multiply the two variables

6* 25 = 150

so the answer is sqrt{150}

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In the figure, TP and TS are opposite rays. TQ bisects &lt; RTP.
Ket [755]

Answer:

search-icon-image

Class 9

>>Maths

>>Quadrilaterals

>>Quadrilaterals and Their Various Types

>>In Fig. 6.43, if PQ PS, PQ∥ SR, SQR = 2

Question

Bookmark

In Fig. 6.43, if PQ⊥PS,PQ∥SR,∠SQR=28

0

and ∠QRT=65

0

, then find the values of x and y.

463685

expand

Medium

Solution

verified

Verified by Toppr

Given, PQ⊥PS,PQ∥SR,∠SQR=28

∘

,∠QRT=65

∘

According to the question,

x+∠SQR=∠QRT (Alternate angles as QR is transversal.)

⇒x+28

∘

=65

∘

⇒x=37

∘

Also ∠QSR=x

⇒∠QSR=37

∘

Also ∠QRS+∠QRT=180

∘

(Linear pair)

⇒∠QRS+65

∘

=180

∘

⇒∠QRS=115

∘

Now, ∠P+∠Q+∠R+∠S=360

∘

(Sum of the angles in a quadrilateral.)

⇒90

∘

+65

∘

+115

∘

+∠S=360

∘

⇒270

∘

+y+∠QSR=360

∘

⇒270

∘

+y+37

∘

=360

∘

⇒307

∘

+y=360

∘

⇒y=53

∘

Step-by-step explanation:

please mark me as brainlist please

6 0
2 years ago
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