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grigory [225]
2 years ago
11

Write an equation in standard form of the hyperbola described.

Mathematics
1 answer:
marishachu [46]2 years ago
5 0

Check the picture below, so the hyperbola looks more or less like so, so let's find the length of the conjugate axis, or namely let's find the "b" component.

\textit{hyperbolas, horizontal traverse axis } \\\\ \cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h\pm a, k)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2 + b ^2} \end{cases} \\\\[-0.35em] ~\dotfill

\begin{cases} h=0\\ k=0\\ a=2\\ c=4 \end{cases}\implies \cfrac{(x-0)^2}{2^2}-\cfrac{(y-0)^2}{b^2} \\\\\\ c^2=a^2+b^2\implies 4^2=2^2+b^2\implies 16=4+b^2\implies \underline{12=b^2} \\\\\\ \cfrac{(x-0)^2}{2^2}-\cfrac{(y-0)^2}{12}\implies \boxed{\cfrac{x^2}{4}-\cfrac{y^2}{12}}

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Answer:

x=32°

Step-by-step explanation:

The law of sines is a property of all triangles that relates the sides and angles of a triangle. This property states the following:

\frac{sin(a)}{A}=\frac{sin(b)}{B}=\frac{sin(c)}{C}

Where side (A) is the side opposite angle (<a), side (B) is the side opposite angle (<b), and side (C) is the property opposite angle (<c).

Substitute each of the sides and respective angles into the formula, and solve for the unknown angle (<x). Please note that a triangle with two congruent sides (referred to as an isosceles triangle) has a property called the base angles theorem. This states that the angles opposite the congruent sides in an isosceles triangle are congruent. Therefore, there can be two (<x)'s in this triangle.

\frac{sin(a)}{A}=\frac{sin(b)}{B}=\frac{sin(c)}{C}

\frac{sin(x)}{10}=\frac{sin(116)}{17}=\frac{sin(x)}{10}

One can shorten the equation so it only holds the parts that will play a role in solving this equation,

\frac{sin(x)}{10}=\frac{sin(116)}{17}

Now take the cross product in this equation to simplify it further,

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17(sin(x))=10(sin(116))

Inverse operations, solve this equation for (x),

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