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2 years ago

Pls help this is my last problem and I need to pass this class?!?

Mathematics

2 answers:

densk [106]2 years ago

8 0

Answer:

A = 50°

Step-by-step explanation:

$(2x - 10) + (x + 30) + 70 = 180 \\ 2x + x = 180 + 10 - 30 - 70 \\ 3x = 90 \\ x = \frac{90}{3} \\ x = 30$

Then

$a = 2x - 10 \\ a = 2(30) - 10 \\ a = 60 - 10 \\ a = 50$

Karolina [17]2 years ago

8 0

$\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}$

Actually Welcome to the Concept of the Triangles.

Since we know that, the Angle sum property of a triangle is equal to 180°.

means that, <A + <B + <C = 180°

so we can write as,

==> 2x-10 + x + 30 +70 = 180°

===>3x +90 = 180

==> 3x = 90

hence, x = 30°

so now, substitute angle x,

So angle A is => 2(30)-10 => 60-10 = 50°

hence Angle A = 50°.

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$We\ are\ given,\\3x-2y=-6\\5x-2y=7\\Considering\ this\ system\ of\ equations,\\Let\ 3x-2y=-6\ be\ E_1\\Let\ 5x-2y=7\ be\ E_2,\\Hence,\\Multiplying\ E2\ with\ -1, we\ get:\\3x-2y=-6\\-1(5x-2y)=7*-1\\Hence,\\3x-2y=-6\\-5x+2y=-7\\Now,\\Lets\ add\ E_1\ and\ E_2\ together\\Hence,\\(3x-2y)+(-5x+2y)=(-6)+(-7)\\Hence,\\3x-2y-5x+2y=-13\\Arranging\ And\ Adding\ Like\ terms,\ we\ have:\\3x-5x-2y+2y=-13\\Hence,\\-2x+0y=-13\\-2x=-13\\x=\frac{-13}{-2}=\frac{13}{2}$

$Now,\ we\ can\ substitute\ x=\frac{13}{2}\ in\ E_1\ or\ E_2,\\But,\\Here,\ we'll\ substitute\ it\ in\ E1,\\Hence,\\Substituting\ x=\frac{13}{2}\ in\ E1,\ we\ have:\\3*\frac{13}{2}-2y=-6\\\frac{39}{2}-2y=-6\\-2y=-6- \frac{39}{2}\\-2y=\frac{-12-39}{2}\\-2y=\frac{-51}{2}\\y=\frac{-51}{2*-2}=\frac{51}{4}\\Hence,\\x=\frac{13}{2}, y=\frac{51}{4}$

4 0

2 years ago

4. See if you can find "like-terms" in the expression and

WITCHER [35]

Answer:

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We need to find like terms and simplify the expression $4- 2x + x^2 + 5x + 12 + 2x^2$

Like terms: The terms who have same variable and exponent are called like terms.

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So, after finding like terms and solving, we get $\mathbf{3x^2+3x+16}$

Note: In the question given we have - and + sign with the term 5x i.e 4- 2x + x^2 -+ 5x + 12 + 2x^2

I have solved using +5x, but if the term is -5x then the solution will be:

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