All categories

2 years ago

The odds of winning a contest are 3:7. What is the probability winning the contest?

Mathematics

1 answer:

DiKsa [7]2 years ago

5 0

Answer:

0.3

Step-by-step explanation:

Given: The odds of winning a contest are 3:7

To find: probability of winning the contest

Solution:

Probability refers to chances of occurrence of an event.

Odds are defined as (chances for success) : (chances against success)

Probability of winning = (chances for success) : (chances for success + chances against success)

As odds of winning a contest are 3:7,

(chances for success) : (chances against success) = 3:7

So,

Probability of winning the contest = $\frac{3}{3+7} =\frac{3}{10}=0.3$

Read more on puzzles here

brainly.com/question/16999211

3 0

2 years ago

Find the measure of arc DB.

mafiozo [28]

ñ!

$.30261 {23680x}^{?}$

4 0

2 years ago

135° Solve for <2. 62 = [?] 45° &2 86° Enter

andrey2020 [161]

Answer:

$\displaystyle \angle2 = {49}^{ \circ}$

Step-by-step explanation:

remember that,

if a side of a triangle is extended then exterior angle so formed equal to the sum of the two opposite interior angles

thus our equation is

$\displaystyle \angle2 + {86}^{ \circ} = {135}^{ \circ}$

cancel out 86° from both sides:

$\displaystyle \angle2 = {49}^{ \circ}$

hence,

the measure of the missing angle is 49°

6 0

2 years ago

Read 2 more answers

The heights in inches of orangutans Are normally distributed with a population standard deviation of 3" and an unknown populatio

CaHeK987 [17]

Answer: The 95% confidence interval is approximately (55.57, 58.43)

======================================================

Explanation:

At 95% confidence, the z critical value is about z = 1.960 which you find using a table or a calculator.

The sample size is n = 17

The sample mean is xbar = 57

The population standard deviation is sigma = 3

The lower bound of the confidence interval is

L = xbar - z*sigma/sqrt(n)

L = 57 - 1.960*3/sqrt(17)

L = 55.5738905247863

L = 55.57

The upper bound is

U = xbar + z*sigma/sqrt(n)

U = 57 + 1.960*3/sqrt(17)

U = 58.4261094752137

U = 58.43

Therefore the confidence interval (L, U) turns into (55.57, 58.43) which is approximate.

7 0

3 years ago

A spinner numbered 1 through 5 is spun 3 times. what is the probability of spinning a number less than 3 each time? are these ev

olya-2409 [2.1K]

Prob(spinning a number < 3on 1 spin) = Prob( spinning 1 or 2) = 2/5

Prob( spinning <3 3 times) = 2/5 * 2/5 * 2/5 = 8/125

These events are independent so we multiply the probabilities.

4 0

3 years ago