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Nana76 [90]
3 years ago
11

Graph the inequality on the axes below.

Mathematics
1 answer:
anastassius [24]3 years ago
6 0

Answer:

it would look something like this

Step-by-step explanation:

graph the inequality by finding the boundary line, then shade the appropriate area

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What is 2/3 plus 2 1/3?
Gemiola [76]
2/3 plus 2 1/3 is 3 because 2/3+1/3=1 and 1+2=3.
4 0
3 years ago
Read 2 more answers
In the following figure, the square ABCD is inscribed in the circle centered at point P. What is the area of the circle?
Ainat [17]

Answer:

A_{Circle} \approx 39.24\: units^2

Step-by-step explanation:

Square ABCD is inscribed in a circle with center P such that BC = 5 units.

BD will be diagonal of the square as well as diameter of the circle.

BD = BC\times\sqrt 2

\implies BD = 5\sqrt 2

-> Diameter of the circle (d) = 5\sqrt 2

-> Radius of the circle (r) = 2.5\sqrt 2=3.535\: units

A_{Circle} =\pi(r)^2

\implies A_{Circle} =3.14(3.535)^2

\implies A_{Circle} =3.14(3.535)^2

\implies A_{Circle} =39.2381465

\implies A_{Circle} \approx 39.24\: units^2

8 0
2 years ago
How many different ways can the letters of “football” be arranged
makvit [3.9K]
<h3>Answer:   10,080</h3>

Explanation:

There are 8 letters so there are 8! = 8*7*6*5*4*3*2*1 = 40,320 permutations of those letters. However, the letters "O" and "L" show up twice each, so we must divide by 2! = 2*1 = 2 for each instance this happens.

So,

(8!)/(2!*2!) = (40,320)/(2*2) = (40,320)/4 = 10,080

is the number of ways to arrange the letters of "football".

The reason we divide by 2 for each instance of a duplicate letter is because we can't tell the difference between the two "O"s or the two "L"s. If there was a way to distinguish between them, then we wouldnt have to divide by 2.

3 0
3 years ago
Hello:) anyone able to explain how to solve the equestrian for part (d) ? Thank youu
Anna007 [38]

Answer:

see explanation

Step-by-step explanation:

Given

4a^{4} - 5a² + 1 = 0

Use the substitution u = a², then equation is

4u²  - 5u + 1 = 0

Consider the product of the coefficient of the u² term and the constant term

product = 4 × 1 = 4 and sum = - 5

The factors are - 4 and - 1

Use these factors to split the u- term

4u² - 4u - u + 1 = 0 ( factor the first/second and third/fourth terms )

4u(u - 1) - 1(u - 1) = 0 ← factor out (u - 1) from each term

(u - 1)(4u - 1) = 0

Equate each factor to zero and solve for u

u - 1 = 0 ⇒ u = 1

4u - 1 = 0 ⇒ 4u = 1 ⇒ u = \frac{1}{4}

Convert u back into terms of a, that is

a² = 1 ⇒ a = ± 1

a² = \frac{1}{4} ⇒ a = ± \frac{1}{2}

Solutions are a = ± 1 , a = ± \frac{1}{2}

7 0
3 years ago
B) Solve<br> (i)<br> 9x = 36
Vaselesa [24]

Answer:

4

Step-by-step explanation:

3 0
3 years ago
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