The mean age of 6 women in an office is 25 years old.

The wavelength of red light in a spectrum is about 0.0000007 meters. Which

Nana76 [90]

Answer:

$0.0000007$

And if we count the number of zeros before the number 7, we can rewrite the number like this:

$7x10^{-7}$

We cansolve this problem also counting the number of positions that we need to move the decimal point to the right in order to obtain the first number (7)

And the best option would be:

B. 7 x 10-7

Step-by-step explanation:

For this case we have the following number given:

$0.0000007$

And if we count the number of zeros before the number 7, we can rewrite the number like this:

$7x10^{-7}$

We cansolve this problem also counting the number of positions that we need to move the decimal point to the right in order to obtain the first number (7)

And the best option would be:

B. 7 x 10-7

8 0

3 years ago

Help pls ill give extra points :))

ahrayia [7]

Answer:

it is 19

Step-by-step explanation:

follow the order of operations

P

E

M

D

A

S

7 0

3 years ago

Read 2 more answers

Which graph shows a linear function.<br> A) <br> B) <br> C) <br> D)

Hitman42 [59]

The First one (A) because it’s a straight line

3 0

3 years ago

Read 2 more answers

How would you rename both factors of 61*69

natulia [17]

4209Answer:

Step-by-step explanation:

Magic

5 0

3 years ago

For each function below, determine whether or not the function is injective and whether or not the function is surjective. (You

Harlamova29_29 [7]

Answer: First, injective means that for every y, there is only one x such f(x) = y, and surjective means that if f is a function that goes from the set {x} to the set {y}, for every element y in the codomain there is at least one element x in the domain such f(x) = y

(a) f:R----> + R given by f(x) = x2 (i guess you written $x^{2}$ )

The function is not injective, because f(-2) = f(2), and is surjective, because the codomain is +R, and $x^{2}$ is always a positive real number.

(b) f:N----> + N given by f(n) = n2 (i guess you written $n^{2}$ )

As the naturals have no negative numbers, in this case the function is injective, but isn't surjective, because there is no number that when squared is equal to 5, for example.

(c) f: Zx Z → Z given by f(n, k) = n +k:

here the domain is of the form (n,k) and the function is n +k, so the numbers (z,w) and (w,z) return the same value when evaluated in f, then f is not injective. And is easy to see that f is surjective, because in the sum you can reach al the integers on the codomain.

3 0

3 years ago