The answer is c to my calculations.
Answer: Hello!
Let's start with the word TRISKAIDEKAPHOBIA wich has 17 letters (some of them repeat, but it does not matter in this problem)
We want to know how many permutations we can do with 17 letters: then think this way, Lets compose a word. The first letter of this word has 17 options, the second letter of the word has 16 options (you already took one of the set) the third letter of the word has 15 options, and so on.
The total number of permutations is the product of the number of options that you have for each letter, this is:
17*16*15*14*....*3*2*1 = 17! = 3.6e+14
(b) FLOCCINAUCINIHILIPILIFICATION now we have 30 letters in total, using the same reasoning as before, here we have 30! permutations; this is
30! = 2.65e+32
(c) PNEUMONOULTRAMICROSCOPICSILICOVOLCANOCONIOSIS: now there are 47 letters.
then P = 47! = 2.59e+59
(d) DERMATOGLYPHICS: here are 18 letters, then:
p = 18! = 6.4e+15
Answer: -23
Step-by-step explanation:
Okay so the table represents B, in one hour of work, the person will make 18.25 (you get this by dividing 36.50 by two because that is how much they made in two hours, we need to know how much they make in one)
Therefore, the equation for A, which has to be less than B, would be either be Y=18x or Y=18.1x
