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Kay [80]
3 years ago
5

Bret kicks a soccer ball straight up into the air worth an initial velocity of 25 m/s from a height of 1 m. After how many secon

ds will the soccer ball land?
A. 5 s

B. 5.14 s

C. 6.5 s

D. 7 s
Mathematics
1 answer:
grin007 [14]3 years ago
4 0
The answer is B i think
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Give the excluded values for the rational equation.<br><br> (3x)/(x-4)-(x+3)/(x+4)=(2x+7)/(x^(2)-16)
scoray [572]

\frac{3x}{x-4}  - \frac{x+3}{x-4} = \frac{2x+7}{x^2-16}

We factor the denominators

Factor x^2 - 16

x^2 - 4^2

We use a^2 - b^2 = (a+b)(a-b)

so x^2 - 4^2 = (x+4)(x-4)

Replace it in the given equation

\frac{3x}{x-4}  - \frac{x+3}{x-4} = \frac{2x+7}{(x+4)(x-4)}

Excluded values are the values that makes the denominator 0

we have (x-4)  and (x+4) in the denominator

We set the denominator =0 and solve for x

x-4 =0

Add 4 on both sides

x= 4

x+4=0

subtract 4 onboth side

so x= -4

Excluded values are x=-4 and x=4




8 0
3 years ago
Read 2 more answers
In a class of 19 students, 3 are math majors. A group of four students is chosen at random. (Round your answers to four decimal
KatRina [158]

Answer:

(a) The probability is 0.4696

(b) The probability is 0.5304

(c) The probability is 0.0929

Step-by-step explanation:

The total number of ways in which we can select k elements from a group n elements is calculate as:

nCx=\frac{n!}{x!(n-x)!}

So, the number of ways in which we can select four students from a group of 19 students is:

19C4=\frac{19!}{4!(19-4)!}=3,876

On the other hand, the number of ways in which we can select four students with no math majors is:

(16C4)*(3C0)=(\frac{16!}{4!(16-4)!})*(\frac{3!}{0!(3-0)!})=1820

Because, we are going to select 4 students form the 16 students that aren't math majors and select 0 students from the 3 students that are majors.

At the same way, the number of ways in which we can select four students with one, two and three math majors are 1680, 360 and 16 respectively, and they are calculated as:

(16C3)*(3C1)=(\frac{16!}{3!(16-3)!})*(\frac{3!}{1!(3-1)!})=1680

(16C2)*(3C2)=(\frac{16!}{2!(16-2)!})*(\frac{3!}{2!(3-1)!})=360

(16C1)*(3C3)=(\frac{16!}{1!(16-1)!})*(\frac{3!}{3!(3-3)!})=16

Then, the probability that the group has no math majors is:

P=\frac{1820}{3876} =0.4696

The probability that the group has at least one math major is:

P=\frac{1680+360+16}{3876} =0.5304

The probability that the group has exactly two math majors is:

P=\frac{360}{3876} =0.0929

6 0
3 years ago
The product of two odd numbers is always odd, why?
LekaFEV [45]

Answer:

Because you are adding the same odd value for odd number of times.

Step-by-step explanation:

5 0
4 years ago
Maths question I'm struggling with.
Alex17521 [72]

Answer:

A = 2.63

B = 2

Step-by-step explanation:

To find the population density, what we need to do simply is divide the population by the area of the UK

mathematically, that would be;

(6.41 * 10^7)/243,610 = 263.125

To the nearest whole person= 263 people/ square meter

So now we want to write 263 in standard form = 2.63 * 10^2

So this means A = 2.63 and B = 2

6 0
3 years ago
Jim gets a simple interest loan for $1500 for 2 years and has 7.5% interest. How much does he pay in total for his loan includin
densk [106]

Answer:

$17225

Step-by-step explanation:

convert percent values to decimals

7.5/100=.075

plug into equations where x=total interest and y is total loan pay

1500*.075*2=x

1500+x=y

solve equation 1

1500*.075*2=x

225=x

solve equation 2 now that we know total interest

1500+225=y

17225

(i would appreciate a thanks and rating my boy)

4 0
4 years ago
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