Answer:
<em>The net force that acts on the sailboat has a magnitude of 217 N and is applied at an angle of 64° north of east.</em>
Explanation:
<u>Mechanical Force</u>
The second Newton's law states the net force exerted by an external agent on an object of mass m is:
Where is the acceleration of the object. Note both the force and the acceleration are vectors. The relationship between them is the mass, a scalar.
This means the net force and the acceleration have the same direction.
The sailboat has a mass m= 350 Kg and moves at a=0.62 m/s^2. The magnitude of the net force acting on the boat is:
As stated above its direction is the same as the acceleration, thus:
The net force that acts on the sailboat has a magnitude of 217 N and is applied at an angle of 64° north of east.
This would have to be jogging
Answer:
5m/s/s
Explanation:
10N bc you subtract 10N from 20N and you get 10
a=f/m
F=10N
m=2kg
10/2=5
Answer:
D. Both occur between objects independently whether they are in contact or not.
Explanation:
- The gravitational force is a force that is exerted between two (or more) objects having mass. This force is always attractive and its magnitude is given by
where G is the gravitational constant, m1 and m2 are the two masses, and r is the distance between the two masses.
- The electrical force is a force that is exerted between two (or more) objects having electrical charge. It can be either attractive or repulsive, depending on the sign of the two charges, and its magnitude is given by
where k is the Coulomb's constant, q1 and q2 are the two charges, and r the distance between the two charges.
Looking at both formulas, we see that the two forces are present even when the two objects are not in contact with each other (in fact, r can assume any value in the formula). They are said to be non-contact forces. Therefore, the correct option is
D. Both occur between objects independently whether they are in contact or not.
If the spaceship's Physicist happens to be hanging out of one side
of the ship, and he measures the speed of the photons as they pass
him and leave the ship, he'll see them passing him at 'c' ... the speed
of light.
When those photons pass somebody who happens to be in their
path, and he decides to measure their speed, he'll see them move
past him at 'c' ... the speed of light.
It doesn't matter whether the observer who measures them is
moving, or at what speed.
And it doesn't matter what source the photons come from, or
whether the source is moving, or at what speed.
And it doesn't matter what the photons' wavelength/frequency is ...
anything from radio to gamma rays.
The photons pass everybody at 'c' ... the speed of light.
Yes, I hear you. That can't be true. It's crazy.
Maybe it's crazy, but it's true.