Answer:
A)A=0.075 m
B)v= 0.21 m/s
Explanation:
Given that
m = 0.75 kg
K= 13.5 N
The natural frequency of the block given as

The maximum speed v given as

A=Amplitude


A=0.075 m
A= 0.75 cm
The speed at distance x



v= 0.21 m/s
The answer is evolution. When a specifies evolves over time they change and adapt to their environment.
Force = mass * acceleration = 1500kg * 8m/s²
The higher you go the more potential energy there is, and the lower it is the more kinetic energy there is, so the more kinetic energy there is the higher the ball will bounce.
Are their any multiple choice questions? Also you said, "<span>Birds that have adapted to temperatures in their environment must find a way to adapt." It says they already adapted lol</span>