Answer: (A) 3.0=A
Explanation: In order to explain this problem we have to use the OHM law, given by: V=R*I
Besides, we have to consider the resitance equivalent for a parallel connection. This is given by:
1/Re=1/R1+1/R2
If we connect the same resistance, the equivalent resistance is R/2.
Initlally the current is 1.5 A when one resistance is connected to the batttery. When a second resistance with the same value is connected in parallel to the battery, we have V=Re*Ifinal= (R/2)*Ifinal
also we know that V=R*Iinitial so Iinitial=V/R
then Ifinal= 2*V/R=2*Iinitial
The density of the nickel was greater than that of the quarter and penny, thus, the results supports the hypothesis.
<h3>What is density of substance?</h3>
The density of a substance is a measure of how tightly-packed the particles of the substance are.
Density is calculated as the ratio of the mass of the substance and the volume of the substance.
The hypothesis of the lab to compare the densities of a penny, a nickel, and a quarter is:
- If the nickel has a greater density than the quarter and penny, then it will have a greater mass to volume ratio. If the nickel has a lower density than the quarter and penny, then it will have a lower mass-to-volume ratio.
The average mass and the average volume of a penny, a nickel, and a quarter are then used to determine the density of each coin.
Based on obtained results, it would be found that the density of the nickel was greater than that of the quarter and penny. Therefore, the results supports the hypothesis.
In conclusion, the density of a substance depends on the mass and the volume.
Learn more about density at: brainly.com/question/1354972
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I'm assuming you want the first law of thermodynamics.
The First Law of Thermodynamics states that heat is a form of energy and cannot be created or destroyed. It can, however, be transferred from one location to another and can be converted into other forms of energy.
Answer:
a) The minimum thickness of the oil slick at the spot is 313 nm
b) the minimum thickness be now will be 125 nm
Explanation:
Given the data in the question;
a) The index of refraction of the oil is 1.20. What is the minimum thickness of the oil slick at that spot?
t
= λ/2n
given that; wavelength λ = 750 nm and index of refraction of the oil n = 1.20
we substitute
t
= 750 / 2(1.20)
t
= 750 / 2.4
t
= 312.5 ≈ 313 nm
Therefore, The minimum thickness of the oil slick at the spot is 313 nm
b)
Suppose the oil had an index of refraction of 1.50. What would the minimum thickness be now?
minimum thickness of the oil slick at the spot will be;
t
= λ/4n
given that; wavelength λ = 750 nm and index of refraction of the oil n = 1.50
we substitute
t
= 750 / 4(1.50)
t
= 750 / 6
t
= 125 nm
Therefore, the minimum thickness be now will be 125 nm