The energy levels of an atom are occupied by__

A 26-kg chandelier hangs from a ceiling on a vertical 4.0-m-long wire. what horizontal force would be necessary to displace its

-Dominant- [34]

First of all you have that the force that is in cable in its vertical posibion is:
Fy = m * g
Fy = (26) * (9.8) = 254.8 N
Then, the force in horizontal direction will be:
Tan (x) = Fy / Fx
Clearing:
Fx = Fy / tan (x)
Substituting values:
Fx = (254.8) / (0.17 / 4)
Fx = 5995.29 N
Answer:
The horizontal force that would be necessary to displace its position 0.17 m to one side is 5995.29 N

8 0

3 years ago

Different forces were applied to five balls, and each force was applied for the same amount of time. The data is in the table. A

Annette [7]

The magnitude of impulse on Ball A will become twice (doubles). Hence, option (c) is correct.

Impulse:

The effect of applied force acting for a very small interval of time is known as Impulse.

Given data:

The initial magnitude of the force on Ball A is, F = 50 N.

The time interval for the applied force on Ball A is, t = 1.25 s.

And the impulse at initial on ball A is, I = 62.5 N-s.

Now, if force on ball A doubles, which means new magnitude of force is,

F' = 2F

F' = 2 × 50

F' = 100 N

For same time interval, the new impulse on Ball A is given as,

I' = F' × t

Solving as,

I' = 100 × 1.25

I' = 125 N-s

Taking the ratio of both the impulses as,

I' / I = 125/62.5

I' = 2 I

Thus, we can conclude that the magnitude of impulse on Ball A will become twice (doubles). Hence, option (c) is correct.

Learn more about the impulse here:

brainly.com/question/904448

7 0

3 years ago

An open pipe is 1.42 m long

lora16 [44]

Answer:

the fundamental frequency produced by the open pipe is 120.78 Hz

Explanation:

Given;

length of the open pipe, L = 1.42 m

speed of sound in air, v = 343 m/s

The length of the open pipe for the fundamental frequency is equivalent to half of wavelength;

$L = \frac{\lambda}{2} \\\\\lambda = 2L$

The fundamental frequency produced by the open pipe is calculated as;

$f_o = \frac{v}{\lambda} \\\\f_o = \frac{v}{2L} \\\\f_o = \frac{343}{2 \times 1.42} \\\\f_o = 120.78 \ Hz$

Therefore, the fundamental frequency produced by the open pipe is 120.78 Hz

6 0

3 years ago

A truck drives with a constant linear speed v_iv i v, start subscript, i, end subscript down a road with two curves. The first

Alex

Answer:

(C) Decreases by factor of 3

Explanation:

Centripetal acceleration is given by

$a = \dfrac{v^2}{r}$

where v is the linear velocity and r is the radius of the curve.

Let the centripetal acceleration on the curve of radius R be $a_1$ .

Then

$a_1 = \dfrac{v_i^2}{R}$

Let the centripetal acceleration on the curve of radius 3R be $a_2$ .

Then

$a_2 = \dfrac{v_i^2}{3R} = \dfrac{1}{3}\dfrac{v_i^2}{R} = \dfrac{1}{3}a_1$

Here, we see that the acceleration decreases by a factor of 3.

7 0

3 years ago

Li and Raj are playing football. They take turns trying to run past each other with the football. Li weighs 125 pound and Raj we

Elenna [48]

Answer:

Li has less mass and therefore less inertia, so he can change his motion more easily than Raj.

Explanation:

Inertia describes the resistance of an object to any change in its state of motion, and it depends on the mass of the object only. In particular:

- if an object has a large inertia (large mass), then it is more difficult to change its state of motion (i.e. to put it in motion, or to slow it down, or to change its direction of motion)

- if an object has small inertia (small mass), then it is more easy to change its state of motion

In this problem, Li has less mass than Raj, so he has less inertia, therefore he can change his motion more easily than Raj.

3 0

4 years ago

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The energy levels of an atom are occupied by___?