If point

is on the unit ircle, then:

Since, the point is in the second quadrant, x is negative.
Thus,

Part A:

Therefore,

.
Part B:

Therefore,
Answer:
(f/g)(5) = 22
Step-by-step explanation:
All we need to do is plug in 5 for x in both f(x) and g(x) then divide the result of f(x) and g(x) to find our final answer.
Step 1: Plug in 5 for x
f(x) = 7(5) + 4(5) = 55
g(x) = 1/2(5) = 2.5
Step 2: Divide f(x) by g(x)
f(5)/g(5) = 55/2.5 = 22
And we have our final answer!
<h3>
Answer:</h3>
<h3>
Step-by-step explanation:</h3>
If the trapezoid is isosceles, angles A and C are supplementary, so ...
... (4x+4) +(7x+11) = 180
... 11x +15 = 180 . . . . . . collect terms
... 11x = 165 . . . . . . . . . subtract 15
... x = 15 . . . . . . . . . . . . divide by the coefficient of x
And angles C and E are congruent.
... 4·15 +4 = 21y +1
... 63 = 21y . . . . . subtract 1
... 3 = y . . . . . . . . divide by the coefficient of y
Answer:
read below
Step-by-step explanation:
Alright, archtan /
tan
−
1
(
x
)
is the inverse of tangent. Tan is
sin
cos
. Like the inverse of sin, the inverse of tan is also restricted to quadrants 1 and 4.
Knowing this we are solving for the inverse of tan -1. We are basically being asked the question what angle/radian does tan(-1) equal. Using the unit circle we can see that tan(1)= pi/4.
Since the "Odds and Evens Identity" states that tan(-x) = -tan(x). Tan(-1)= -pi/4.
Knowing that tan is negative in quadrants 2 and 4. the answer is in either of those two quadrants. BUT!!! since inverse of tan is restricted to quadrants 1 and 4 we are left with the only answer -pi/4.
the answer is m=-3n-5/2 or n=2m+5/6