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n200080 [17]
3 years ago
10

or the end-of-year party, Mt. Rose Middle School ordered 112 pizzas. There were eight fewer veggie pizzas than there were pepper

oni pizzas. There were three times as many combo pizzas as pepperoni pizzas. Use the 5-D Process to define a variable and write an equation for this situation. Then determine how many of each kind of pizza were ordered.

Mathematics
2 answers:
marshall27 [118]3 years ago
8 0

Let the number of pepperoni pizzas be x

pepperoni = x

veggie = x - 8    [There were eight fewer veggie than pepperoni]

combo = 3x       [There were three times as many combo as pepperoni]

Given that the total Pizza: 112

x + x - 8 + 3x = 112

5x - 8 = 112

5x = 112 + 8

5x = 120

x = 24

x= 24

x - 8 = 16

3x = 72

So there were 24 pepperoni pizza, 16 veggie pizza and 72 combo pizza

Tresset [83]3 years ago
3 0

Answer:

16 Veggie

24 Pepperoni

72 Combo

Step-by-step explanation:

Working shown in the pic.

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Please help me with this
xenn [34]

Step-by-step explanation:

based on my understanding of the dreidel, this is a regular spinner with 4 equal sides (but different symbols on them, so, we can clearly distinguish between the possible 4 different outcomes).

in other words, this resembles a die with only 4 sides and therefore only 4 equally probable outcomes.

and therefore, the probability to get the specified symbol in 1 attempt is indeed 1/4.

remember, a probability is always desired cases over totally possible cases.

and here, we have one desired outcome out of 4 possible outcomes. hence the probability of 1/4.

now, we are spinning the dreidel twice.

that means we have now 4×4 = 16 possible outcomes.

but we only want the outcomes, where the specified symbol is showing exactly once - either after the first spin or after the second spin.

so, out of the 16 possible combinations, we want only the ones, where the first spin delivered that result :

1 option on the first spin and 3 options (4 minus the already delivered result) on the second spin : 1×3 = 3.

and the ones, where the second spin delivered the result (but not the first). so, we have 3×1 = 3 options there.

that means we have 6 desired cases out of total 16 possible outcomes, and the probability is

6/16 = 3/8

mathematically we would simply say that the probability is the sum of

the probability of spinning it first combined with the probability of not spinning it second.

the probability of not spinning it first combined with the probability to spin it second.

that is

1/4 × 3/4 = 3/16

+

3/4 × 1/4 = 3/16

-----------------------

6/16 = 3/8

I don't know the options you can select, but I hope you understand the principles I explained. and I gave you the result and the way to calculate it.

so, hopefully you find the fitting options.

8 0
2 years ago
Suppose that two openings on an appellate court bench are to be filled from current municipal court judges. The municipal court
Ksju [112]

Answer:

(a)\dfrac{92}{117}

(b)\dfrac{8}{39}

(c)\dfrac{25}{117}

Step-by-step explanation:

Number of Men, n(M)=24

Number of Women, n(W)=3

Total Sample, n(S)=24+3=27

Since you cannot appoint the same person twice, the probabilities are <u>without replacement.</u>

(a)Probability that both appointees are men.

P(MM)=\dfrac{24}{27}X \dfrac{23}{26}=\dfrac{552}{702}\\=\dfrac{92}{117}

(b)Probability that one man and one woman are appointed.

To find the probability that one man and one woman are appointed, this could happen in two ways.

  • A man is appointed first and a woman is appointed next.
  • A woman is appointed first and a man is appointed next.

P(One man and one woman are appointed)=P(MW)+P(WM)

=(\dfrac{24}{27}X \dfrac{3}{26})+(\dfrac{3}{27}X \dfrac{24}{26})\\=\dfrac{72}{702}+\dfrac{72}{702}\\=\dfrac{144}{702}\\=\dfrac{8}{39}

(c)Probability that at least one woman is appointed.

The probability that at least one woman is appointed can occur in three ways.

  • A man is appointed first and a woman is appointed next.
  • A woman is appointed first and a man is appointed next.
  • Two women are appointed

P(at least one woman is appointed)=P(MW)+P(WM)+P(WW)

P(WW)=\dfrac{3}{27}X \dfrac{2}{26}=\dfrac{6}{702}

In Part B, P(MW)+P(WM)=\frac{8}{39}

Therefore:

P(MW)+P(WM)+P(WW)=\dfrac{8}{39}+\dfrac{6}{702}\\$P(at least one woman is appointed)=\dfrac{25}{117}

5 0
3 years ago
Please help me! I will give it 5 stars and I will heart the answer!
andrew11 [14]

Answer:

Haha there is no question

Step-by-step explanation:

4 0
3 years ago
CAN SOMEONE HELP ME PLEASE? ASAP. CAN SOMEONE ANSWER THIS ASAP PLEASE? I NEED HELP!!
Sveta_85 [38]
Honestly I don’t even know what this is sorry I tried
7 0
3 years ago
Read 2 more answers
If f(x)=7(x-1)+8, what is the value of f(1)<br>​
irga5000 [103]

Answer:

8

Step-by-step explanation:

f(1)=7(1-1)+8

f(1)=7(0)+8

f(1)=0+8

f(1)=8

4 0
3 years ago
Read 2 more answers
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