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kramer
3 years ago
9

How do I solve this question?

Mathematics
1 answer:
Tanya [424]3 years ago
6 0
Before attempting to solve this question, we must first know three things.

1. A straight line has a measure of 180 degrees.

2. When two angles add up to 180 degrees, those angles are called supplementary.

3. The interior angles of a triangle add up to 180 degrees.

We can see ∠ECT = 180 degrees.

∠DCT is supplementary to ∠DCE.

∠DCT = 140 degreees
∠DCE = x degrees

x + 140 = 180

Solve for x.

x + 140 = 180
x = 40 <-- Subtract 140 from each side

∠DCE = 40 degrees

We know the two interior angles of ΔDEC.

45 + 40 + x = 180

Solve for x.

45 + 40 + x = 180
85 + x = 180 <-- Combine like terms
x = 95

So, the missing angle is equal to 95 degrees.
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True or false: 3^-1 x 3^-1=3^1
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Answer:

the answer I got is false

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2 years ago
Emma pays 10$ to join a gym. For the first 5 months she pays a monthly 15$ membership fee. For problems 6-7 use the explicit rul
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Answer: For the first 5 months she pays a monthly$15 membership fee. Use the explicit rule f(n) = 15n + 10

Step-by-step explanation:

3 0
3 years ago
Math-- Farmer Bill has 500 meters of fencing and wants to enclose a rectangular plot that borders on a river. If farmer Bill doe
bixtya [17]

Answer:

Required dimensions of the rectangle are L = 200 m, W  = 100 m

The  largest area that can be enclosed is 20,000 sq m.

Step-by-step explanation:

The available length of the fencing = 500 m

Now, Perimeter of a rectangle = SUM OF ALL SIDES  = 2(L+B)

But, here once side of the rectangle is NOT FENCED.

So, the required perimeter  

= Perimeter of Complete field - Boundary of 1 open side

= 2(L+ W)   - L  = 2W + L

Now, fencing is given as 500 m

⇒  2W + L  = 500

Now, to maximize the length and width:

put L = 200, W = 100

we get 2(W) +L =  2(200) + 100 = 500 m

Hence, required dimensions of the rectangle are L = 200 m, W  = 100 m

The maximized area = Length x Width

                                   = 200 m x 100  m = 20, 000 sq m

Hence, the  largest area that can be enclosed is 20,000 sq m.

6 0
3 years ago
According to a recent​ publication, the mean price of new mobile homes is ​$63 comma 800. Assume a standard deviation of ​$7900.
wolverine [178]

Answer:

a. For n=25, the mean and standard deviation of the prices of the mobile homes all possible sample mean prices are ​$63,800 and ​$1,580​, respectively.

b. For n=50, the mean and standard deviation of the prices of the mobile homes all possible sample mean prices are ​$63,800 and ​$1,117​, respectively.

Step-by-step explanation:

In this case, for each sample size, we have a sampling distribution (a distribution for the population of sample means), with the following parameters:

\mu_s=\mu=63,800\\\\\sigma_s=\sigma/\sqrt{n}=7,900/\sqrt{n}

For n=25 we have:

\mu_s=\mu=63,800\\\\\sigma_s=\sigma/\sqrt{n}=7,900/\sqrt{25}=7,900/5=1,580

The spread of the sampling distribution is always smaller than the population spread of the individuals. The spread is smaller as the sample size increase.

This has the implication that is expected to have more precision in the estimation of the population mean when we use bigger samples than smaller ones.

If n=50, we have:

\mu_s=\mu=63,800\\\\\sigma_s=\sigma/\sqrt{n}=7,900/\sqrt{50}=7,900/7.07=1,117

4 0
4 years ago
I dont understand how to write this 2 problems out in equivalent form
deff fn [24]
Just do 1/8 times 1/8. Hope this helped !!
8 0
3 years ago
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