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egoroff_w [7]
3 years ago
15

solve the following word problem. use x for the unknown value. the average cost of a car in 2013 is said to be 5 less than twice

the cost of a car in 2009. if the average cost of a car in 2013 is $25,000. how much was the average cost of a car in 2009?
Mathematics
1 answer:
Rashid [163]3 years ago
7 0
Let the average cost of car in 2009 be $x, then the average cost of a car in 2013 is 2x - 5
25,000 = 2x - 5
2x = 25,000 + 5 = 25,005
x = 25,005/2 = $12,502.50
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A recipe uses 2 cups of sugar to make 32 brownies. How many cups of sugar are needed to make 72 brownies?
White raven [17]
4 and a fourth. This is because 2 * 32 is 64, then you need to divide 32 by 4 to get 8 left. I am sorry if I solved this incorrectly. Make sure to check with your coordinator ( teacher ) or parent to help solve this. 32 is divided into 4ths.
5 0
3 years ago
-7c+9=c+1 <br> If you could also show how you did it i would appreciate it
Step2247 [10]
-7c+9=c+1    (subtract c on both sides)
-8c+9=1    (subtract 9 on both sides)
-8c=-8     (divide by -8 on both sides to get c by its self)
c=1
your answer is 1.
5 0
3 years ago
Read 2 more answers
A camera shop purchases a camera for $56.98 and sells it for $102.56. What is the percent of markup?
Amiraneli [1.4K]

Answer:

180%

Step-by-step explanation:

Set up an equation:

Variable x = percent of markup

102.56/56.98 = x/100

Cross multiply

102.56 × 100 = 56.98 × x

10,256 = 56.98x

Divide both sides by 56.98:

179.99297.... = x

Round to nearest whole number:

180 = x

Check your work:

56.98 × 180%

Convert the percentage into a decimal:

56.98 × 1.80

102.564

Round to nearest cent:

102.56

Correct!

8 0
3 years ago
HELP!!!In the expression 100 a/b, if a is greater than b, which statements are true? b ≠ 0. Select all that apply.
MAXImum [283]

Answer:

\large\boxed{\text{The expression is equal to}\ \sqrt[b]{100^a}}\\\boxed{\text{The expression is greater than 100}}

Step-by-step explanation:

a^\frac{m}{n}=\sqrt[n]{a^m}\\\\\text{True statement:}\\\\100^\frac{a}{b}=\sqrt[b]{100^a}\\\\a>b\to\dfrac{a}{b}>1\to\dfrac{a}{b}=1\dfrac{a-b}{b}\\\\100^\frac{a}{b}=100^{1\frac{a-b}{b}}=100^{1+\frac{a-b}{b}}=100^1\cdot100^\frac{a-b}{b}=100\sqrt[b]{100^{a-b}}\\\\a>b\to a-b>0\to100^{a-b}>1\\\\\text{Therefore}\ 100\sqrt[b]{100^{a-b}}>100

4 0
3 years ago
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raketka [301]
L = 4d + 54

after crew worked 33 days...d = 33
L = 4(33) + 54
L = 132 + 54
L = 186...so after 33 days, the crew made a road that measures 186 miles
4 0
3 years ago
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