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Feliz [49]
3 years ago
6

Someone can help me in this please ASAP and explain to me how? THANK YOU

Mathematics
1 answer:
uysha [10]3 years ago
6 0
Answer is c because the solutions are -2 and -5

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Pls help! I will mark brainliest
dolphi86 [110]

Answer:

So the greatest common factor is 3 for sure

Step-by-step explanation:

54x^4y^5z^2

i could be wrong but i am sure that's it

6 0
3 years ago
The perimeter of a parallelogram is 72 inches, and
borishaifa [10]
The answer is C Since its a parallelogram, the opposite side is also 12. 12+12=24, 72-24=48, 48/2=24 which is the other 2 sides
3 0
3 years ago
Read 2 more answers
If the area of the right triangle is 72 what is the value of x
wel

36 i guess ha please that not right

8 0
3 years ago
1 substitute p=5, q=7, r = -2
lora16 [44]

1.

a.) 2q + 5r

2(7) + 5(-2)

14 - 10 = 4


b.) 3(p + 6) + q + r     Plug in the numbers

3(5 + 6) + 7 - 2   Solve inside the parentheses first

3(11) + 7 - 2

33 + 5 = 38


2.

a.) m(3m + 4n)

2(3(2) + 4(3))

2(6 + 12)

2(18) = 36


b.) n²(m + p²)

(3)²(2 + (-5)²)

9(2 + 25)

9(27) = 243


c.) 3m(8 + n) + n²

3(2) (8 + 3) + 3²

6(11) + 9

66 + 9 = 75

3 0
3 years ago
The length of time that an auditor spends reviewing an invoice is approximately normally distributed with a mean of 600 seconds
Bumek [7]
Answer: 11.5% 

Explanation:


Since 1 minute = 60 seconds, we multiply 12 minutes by 60 so that 12 minutes = 720 seconds. Thus, we're looking for a probability that the auditor will spend more than 720 seconds. 

Now, we get the z-score for 720 seconds by the following formula:

\text{z-score} =  \frac{x - \mu}{\sigma}

where 

t = \text{time for the auditor to finish his work } = 720 \text{ seconds}
\\ \mu = \text{average time for the auditor to finish his work } = 600 \text{ seconds}
\\ \sigma = \text{standard deviation } = 100 \text{ seconds}

So, the z-score of 720 seconds is given by:

\text{z-score} = \frac{x - \mu}{\sigma}
\\
\\ \text{z-score} = \frac{720 - 600}{100}
\\
\\ \boxed{\text{z-score} = 1.2}

Let

t = time for the auditor to finish his work
z = z-score of time t

Since the time is normally distributed, the probability for t > 720 is the same as the probability for z > 1.2. In terms of equation:

P(t \ \textgreater \  720) 
\\ = P(z \ \textgreater \  1.2)
\\ = 1 - P(z \leq 1.2)
\\ = 1 - 0.885
\\  \boxed{P(t \ \textgreater \  720)  = 0.115}

Hence, there is 11.5% chance that the auditor will spend more than 12 minutes in an invoice. 
8 0
3 years ago
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