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Nat2105 [25]
3 years ago
7

Here u go lol lol lol

Mathematics
2 answers:
MrMuchimi3 years ago
7 0

Answer:

thanks for the points : D

Step-by-step explanation:

Makovka662 [10]3 years ago
3 0

Step-by-step explanation:

lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol

Tysm dudee

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Write the denominator of the fractiona 7/20 as the product of prime factors
gtnhenbr [62]

Answer:

Step-by-step explanation:

prime factors of 20 = 2 * 2 * 5

\frac{7}{20}=\frac{7}{2*2*5}

5 0
3 years ago
3(x+7)+12x-7(x+1)+9-4x<br> Need answer and explaintion
seraphim [82]

Answer:

4

x

+

23

Step-by-step explanation:

5 0
3 years ago
What is the range of data?
a_sh-v [17]

Answer:

The range of data is 9

Step-by-step explanation:

We know that

range of data = maximum value of data - minimum value of data

Now, we can find maximum value of data

and minimum value of data

so,

maximum value of data =9

minimum value of data =0

now, we can plug these values

and we get

range of data =9-0

range of data =9

6 0
3 years ago
For the given term, find the binomial raised to the power, whose expansion it came from: 220(5x)3(−6y)9.
sukhopar [10]
Answer: (5x - 6y)^{12}
Explanation: For a general binomial expansion, (x + y)^{n}, we know that the powers have to add up to the initial power. This means that the power of x and power of y have to add up to n. This is the binomial theorem.

To further demonstrate this, let's use:
(x + y)^{4}

We can easily expand this. Using Pascal's Triangle, we get:
(x + y)^{4} = x^{4} \cdot y^{0} + 4x^{3} \cdot y^{1} + 6x^{2} \cdot y^{2} + 4x^{1} \cdot y^{3} + x^{0} \cdot y^{4}

As we progress along the expansion, we can see that in each term, the summation of each power remains constant, namely 4.

It doesn't matter what term the binomials are, because the power summation will never change.
This is why we can say that it is raised to the 12th power, and the binomial is:
(5x - 6y).

Thus, we get: (5x - 6y)^{12}
5 0
3 years ago
Under which condition does a light ray striking a concave mirror reflect off parallel to the principal axis?. . . A. when the in
kumpel [21]
When the incident ray passes through the focal point, a light ray striking a concave concave mirror reflect off parallel to the principal axis. The correct option among all the options given in the question is the third option or option "C". I hope the answer comes to your help.
5 0
3 years ago
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