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Rasek [7]
3 years ago
8

NUMERICAL EXPRESSIONS

Mathematics
1 answer:
Flauer [41]3 years ago
8 0
30+8-6

here you go the answer
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The standard form of an absolute value function is f(x) = a|x- h| + k. Which of the following represents the vertex?
valina [46]

Answer:

(h, k) is the point that represents the vertex of this absolute value function

Step-by-step explanation:

Recall that the vertex of an absolute value function occurs when the expression within the absolute value symbol becomes "zero", because it is at this point that the results in sign differ for x-values to the left and x-values to the right of this boundary point.

Therefore, in your case, the vertex occurs at  x = h, and when x = h, then you can find the y-value of the vertex by looking at what f(h) renders:

f(h) = a | h - h | + k = 0 + k = k

Then the point of the vertex is: (h, k)

8 0
4 years ago
Help me pleaseeee I would be happy
spayn [35]

Answer:

how much you have ( tommy plucked 6 apples from a tree)

have nothing  (tommy gave away 6 apples)

have less than 0  ( tommy gave away 6 apples)

6-6=0

Step-by-step explanation:

4 0
3 years ago
Please help me!!!!!!!!!!!!!​
monitta

Answer:  see proof below

<u>Step-by-step explanation:</u>

Use the following Half-Angle Identities:    tan (A/2) = (sinA)/(1 + cosA)

                                                                     cot (A/2) = (sinA)/(1 - cosA)

Use the Pythagorean Identity: cos²A + sin²B = 1

Use Unit Circle to evaluate: cos 45° = sin 45° = \frac{\sqrt2}{2}

<u>Proof LHS → RHS</u>

Given:                       cot\ (22\frac{1}{2})^o-tan\ (22\frac{1}{2})^o

Rewrite Fraction:     cot\ (\frac{45}{2})^o-tan\ (\frac{45}{2})^o

Half-Angle Identity:   \dfrac{sin(45)^o}{1-cos(45)^o}-\dfrac{sin(45)^o}{1+cos(45)^o}

Substitute:                  \dfrac{\frac{\sqrt2}{2}}{1-\frac{\sqrt2}{2}}-\dfrac{\frac{\sqrt2}{2}}{1+\frac{\sqrt2}{2}}

Simplify:                      \dfrac{\frac{\sqrt2}{2}}{\frac{2-\sqrt2}{2}}-\dfrac{\frac{\sqrt2}{2}}{\frac{2+\sqrt2}{2}}

                               =\dfrac{\sqrt2}{2-\sqrt2}-\dfrac{\sqrt2}{2+\sqrt2}

                               =\dfrac{\sqrt2}{2-\sqrt2}\bigg(\dfrac{2+\sqrt2}{2+\sqrt2}\bigg)-\dfrac{\sqrt2}{2+\sqrt2}\bigg(\dfrac{2-\sqrt2}{2-\sqrt2}\bigg)

                               =\dfrac{2\sqrt2+2}{4-2}-\dfrac{2\sqrt2-2}{4-2}

                               =\dfrac{4}{2}

                               = 2

LHS = RHS:  2 = 2  \checkmark

7 0
4 years ago
Msr walkers class set up an online fund with a goal to raise 1280
Fofino [41]

Answer: is brainly broken for u too??

Step-by-step explanation:

3 0
3 years ago
GIVING BRAINLIEST<br> What is the solution to the system of linear equations graphed below?
dolphi86 [110]

Answer:

The first option so (3\frac{1}{2}, -4) is the answer

<u>Skills required: Graphing Knowledge, Systems Knowledge</u>

Step-by-step explanation:

1) The solution to any system is the intersection between any 2 lines or functions. In this case, we are given two functions on a graph, and need to find the solution to them. That is the intersection.

2) We can see the intersection and see that the x-axis value for the coordinate point is around 3 1/2 (or 3.5 -- whatever you prefer), and that the y-axis value for the point is -4.

Therefore, the coordinate point is: (3\frac{1}{2}, -4) since this answer best matches the coordinate values of that point.

==================================================================

Select the first option, have a nice day! :D

7 0
3 years ago
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