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Radda [10]
3 years ago
7

Which of the following is a group of different species living in the same approximate place

Chemistry
2 answers:
lilavasa [31]3 years ago
4 0
Biosphere. it is a place where plant's and animals live together and they r interconnected to eachother
guapka [62]3 years ago
4 0
Community: a group of different species or organisms that live together and interact with each other
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A sample of helium gas has a volume of 620. Ml at a temp of 500 K. If we decrease the temperature to 100K while keeping the pres
Ne4ueva [31]

Answer:

A sample of helium gas has a volume of 620mL at a temperature of 500 K. If we ... to 100 K while keeping the pressure constant, what will the new volume be?

Explanation:

3 0
3 years ago
Where can I get a oxygen isotope analysis comercialy
miskamm [114]

Answer:

Honestly I don't know.

Explanation:

Haha good luck though

6 0
3 years ago
A covalent bond forms a(n) ______________.
DiKsa [7]
The answer is Molecule. After a pair of shared electrons orbit around the nuclei of both atoms
3 0
2 years ago
Read 2 more answers
You carefully weigh out 16.00 g of CaCO3 powder and add it to 64.80 g of HCl solution. You notice bubbles as a reaction takes pl
bulgar [2K]

Answer: Mass of CO_2  produced in this reaction was 6.56 grams

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

CaCO_3(s)+2HCl(aq)\rightarrow H_2O(l)+CO_2(g)+CaCl_2(aq)

Mass or reactants =  Mass of CaCO_3+ mass of HCl = 16.00 + 64.80 = 80.80 g

Mass of products  = mass of aqueous solution + mass of CO_2 + = 74.24 + x g

Mass or reactants = Mass of products

80.80 g = 74.24 + x g

x = 6.56 g

Thus mass of CO_2  produced in this reaction was 6.56 grams

7 0
3 years ago
The solubility product of AgCl is 1.4 x 10-4 at 100°C. Calculate the solubility of AgCl in
marshall27 [118]

Answer:

AgCl=Ag+ + Cl-

1.4×10^-4 =x × x

x²=1.4×10^-4

x=√(1.4×10^-4)

x=0.012

5 0
2 years ago
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